Math Problem Statement

S

Example-Applying the Basic Laws

UNIVERSITY

ample 1.3 Consider a two-mesh network of Fig. 1.22. Express the currents in the three resistances and then write the KVL equation.

Solution

To solve Example 1.3, we need to apply the Kirchhoff's Voltage Law (KVL) to the two-mesh network shown in Fig. 1.22. Since you referred to a figure and I cannot see it, I will assume a basic two-mesh network with three resistors for explanation purposes. If your circuit has a different configuration, feel free to upload a picture.

Step 1: Define the Mesh Currents

In a two-mesh network, there are two loops (meshes). Let's assign the following:

  • Mesh 1 current: I1I_1 (in the clockwise direction)
  • Mesh 2 current: I2I_2 (in the clockwise direction)

Step 2: Label the Resistors

Assume the network has three resistances as follows:

  • R1R_1 in the first mesh,
  • R2R_2 shared by both meshes (between Mesh 1 and Mesh 2),
  • R3R_3 in the second mesh.

Additionally, there may be voltage sources V1V_1 in Mesh 1 and V2V_2 in Mesh 2.

Step 3: Express Currents in the Resistors

For each resistor, the current can be expressed based on the mesh currents:

  • Current in R1R_1: This resistor is only in Mesh 1, so the current is I1I_1.
  • Current in R2R_2: This resistor is shared by both meshes. The current through it is the difference between the two mesh currents, so the current is I1I2I_1 - I_2.
  • Current in R3R_3: This resistor is only in Mesh 2, so the current is I2I_2.

Step 4: Apply Kirchhoff's Voltage Law (KVL)

We now apply KVL to both meshes.

Mesh 1 (Loop 1):

The voltage drops in Mesh 1 are across resistors R1R_1 and R2R_2. By KVL, the sum of voltage drops is equal to the voltage source V1V_1: V1=I1R1+(I1I2)R2V_1 = I_1 R_1 + (I_1 - I_2) R_2

Mesh 2 (Loop 2):

The voltage drops in Mesh 2 are across resistors R2R_2 and R3R_3. By KVL, the sum of voltage drops is equal to the voltage source V2V_2: V2=(I2I1)R2+I2R3V_2 = (I_2 - I_1) R_2 + I_2 R_3

Final Equations

The two KVL equations for the system are:

  1. V1=I1R1+(I1I2)R2V_1 = I_1 R_1 + (I_1 - I_2) R_2
  2. V2=(I2I1)R2+I2R3V_2 = (I_2 - I_1) R_2 + I_2 R_3

You can solve these two simultaneous equations to find the values of I1I_1 and I2I_2. Once you have I1I_1 and I2I_2, you can calculate the current through each resistor using the expressions above.


If you have any additional information about the circuit (like values for resistances or voltage sources), I can help you solve it fully. Do you want more details or clarifications?

Related Questions:

  1. How can Kirchhoff's Current Law (KCL) be applied to the same circuit?
  2. What happens if one of the resistors in the two-mesh network is replaced with a capacitor?
  3. Can the system be solved using matrix methods instead of solving it by hand?
  4. How would the solution change if the current direction in Mesh 2 is counterclockwise?
  5. How can superposition be used to simplify solving for currents in this circuit?

Tip:

When writing KVL equations, always ensure that you maintain consistent sign conventions for voltage drops and rises.

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Math Problem Analysis

Mathematical Concepts

Electrical Circuit Analysis
Kirchhoff's Voltage Law (KVL)
Mesh Analysis

Formulas

KVL Equation: V1 = I1 * R1 + (I1 - I2) * R2
KVL Equation: V2 = (I2 - I1) * R2 + I2 * R3

Theorems

Kirchhoff's Voltage Law (KVL)

Suitable Grade Level

Undergraduate Electrical Engineering