https://file.aiquickdraw.com/mathbot/file/17289595153439rfwbwmv.jpg

Let's break down the problem step by step:

### Given:
- **Initial velocity** \( v_0 = 5 \) knots
- **Acceleration** \( a = 60 \, \text{nmi/hr}^2 \)
- **Time** \( t = 10 \, \text{minutes} = \frac{10}{60} \, \text{hours} = \frac{1}{6} \, \text{hours} \)

### Formula:
The final velocity can be found using the kinematic equation:
\[
v = v_0 + a \cdot t
\]
where:
- \( v \) is the final velocity
- \( v_0 \) is the initial velocity
- \( a \) is the acceleration
- \( t \) is the time

### Calculation:
1. Substitute the known values into the formula:
\[
v = 5 \, \text{knots} + 60 \, \text{nmi/hr}^2 \times \frac{1}{6} \, \text{hr}
\]
2. Simplify the expression:
\[
v = 5 + 60 \times \frac{1}{6} = 5 + 10 = 15 \, \text{knots}
\]

### Conclusion:
The velocity of the vessel at the end of the 10-minute period is **15 knots**.

Would you like a deeper explanation or have any other questions?

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Here are some related questions to consider:
1. What if the time was 15 minutes instead of 10 minutes?
2. How would the result change if the acceleration were negative?
3. Can you derive the distance traveled during this 10-minute interval?
4. What would happen if the initial velocity was 0?
5. How would the result change if the units were different, like meters per second?

**Tip:** Always ensure that units are consistent throughout the calculation, especially when converting between time or speed units!

Starting with a velocity of 5 knots along the positive x-axis, a vessel accelerates for 10 minutes with an acceleration of 60 nmi/hr². What is its velocity at the end of the period of 10 minutes?

Solve a kinematics problem involving a vessel with an initial velocity of 5 knots and an acceleration of 60 nmi/hr² over a 10-minute period. Learn how to calculate the final velocity using the basic kinematic formula for constant acceleration. Suitable for Grades 10-12.

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