Math Problem Statement

The motion of an object is shown in the velocity-time graph. Which of the following best describes the motion of the object?

Solution

The given graph is a velocity vs. time graph, which helps us analyze how an object's velocity changes over time.

Key Observations from the Graph:

  1. From 0 to 5 seconds, the velocity increases linearly from 0 to 3 m/s, indicating positive acceleration.
  2. From 5 to 10 seconds, the velocity decreases linearly from 3 m/s back to 0, indicating negative acceleration (or deceleration).
  3. From 10 to 15 seconds, the velocity remains 0, meaning the object is stationary during this interval.

Evaluating the Answer Choices:

  • (A) "The object is either speeding up or slowing down the entire time."

    • This is incorrect because from 10 to 15 seconds, the object is not moving at all (the velocity is 0 throughout). Thus, it's not always speeding up or slowing down.
  • (B) "The object starts and finishes at the same position."

    • This is correct. Since the velocity returns to 0 and the object stops at the end of the motion, it likely comes back to its starting position.
  • (C) "The object travels in the same direction for the entire time."

    • This is incorrect. The decrease in velocity to 0 between 5 and 10 seconds suggests the object may have reversed direction (although it is not explicitly shown in the graph).
  • (D) "The object undergoes positive acceleration the entire time."

    • This is incorrect. The object has positive acceleration only in the first phase (0 to 5 seconds) but negative acceleration (deceleration) from 5 to 10 seconds.

Correct Answer:

  • (B) The object starts and finishes at the same position.

Would you like further details or have any questions?

Here are 5 follow-up questions you might explore:

  1. How do we calculate displacement from a velocity-time graph?
  2. What is the significance of the slope of a velocity-time graph?
  3. How can you find total distance traveled from this graph?
  4. What is the difference between velocity and speed in such graphs?
  5. How would the graph change if the object did not stop at 15 seconds?

Tip: The area under a velocity-time graph represents the displacement of the object.

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Math Problem Analysis

Mathematical Concepts

Kinematics
Velocity-Time Graph Analysis

Formulas

Displacement = Area under velocity-time graph
Slope = Acceleration

Theorems

Concept of positive and negative acceleration
Interpretation of velocity-time graphs

Suitable Grade Level

Grades 9-12