Math Problem Statement
Solution
Let's solve each part step by step.
Given position function:
(a) Find the body's acceleration each time the velocity is zero.
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Find velocity by differentiating :
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Find when velocity is zero: Divide by 3: Factor: So, and .
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Find acceleration by differentiating :
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Evaluate acceleration at and :
Answer: Acceleration is m/s² at and m/s² at .
(b) Find the body's speed each time the acceleration is zero.
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Set acceleration to zero:
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Find speed at (speed is the absolute value of velocity): Speed = m/s.
Answer: The body's speed when acceleration is zero is m/s.
(c) Find the total distance traveled from to .
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Find when the body changes direction (when velocity is zero in [0,3]):
- We found at , which is in [0,3].
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Find positions at , , and :
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Compute total distance:
- From to :
- From to :
- Total distance = meters.
Answer: The total distance traveled is meters.
Summary of Answers:
- (a) Acceleration when velocity is zero: m/s² at , m/s² at .
- (b) Speed when acceleration is zero: m/s.
- (c) Total distance traveled: meters.
Would you like a more detailed explanation for any part?
Related Questions:
- What is the velocity at ?
- How do we determine when the particle is speeding up or slowing down?
- What is the significance of the acceleration sign in motion analysis?
- Can we determine the average velocity from to ?
- How would the motion change if an additional force acted on the body?
Tip:
To analyze motion problems effectively, always differentiate the position function to get velocity and acceleration before solving! 🚀
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Math Problem Analysis
Mathematical Concepts
Differentiation
Kinematics
Polynomial Equations
Absolute Value
Formulas
Velocity: v(t) = ds/dt
Acceleration: a(t) = dv/dt
Quadratic Equation: ax^2 + bx + c = 0
Distance = |s(t2) - s(t1)|
Theorems
Roots of a quadratic equation
Relationship between velocity and acceleration
Absolute value in distance calculations
Suitable Grade Level
Grades 10-12
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