It seems that you uploaded an image from a quiz showing a physics-related problem about relative motion. The problem involves a man running at 5 m/s, with a car accelerating to catch up with him after a 3-minute head start. Let’s break down the scenario step by step and solve the question.

Problem Summary:

1. Man’s speed: 5 m/s (constant).
2. Car's starting speed: 5 kph (converted to 1.39 m/s).
3. Car’s acceleration: The car accelerates from 1.39 m/s to 50 kph (which is 13.89 m/s) over 5 seconds.
4. Man's head start: 3 minutes = 180 seconds.

We need to calculate:

1. Time for the car to catch up to the man after starting 3 minutes late.
2. Displacement of both the car and the man when they meet.

Let me calculate this for you. I'll start by figuring out the car's motion and then solve for the time and displacement.The results are as follows:

1. Time for the car to catch up to the man: 106.24 seconds.
2. Displacement of the man when they meet: 531.19 meters.
3. Displacement of the car when they meet: 1444.39 meters.

The previous attempt answer of 110.34 seconds and 551.7 meters is close but not entirely accurate based on the given calculations.

Would you like further explanation on any part of the solution? Here are five related questions to expand on this:

1. How is acceleration related to displacement and velocity?
2. How would the answer change if the car's final speed was higher?
3. Why is the relative speed important in determining when the car catches up?
4. What if the man was running at a different speed—how would this affect the outcome?
5. Can we apply these concepts to real-world situations like races?

Tip: Always convert all units to a consistent system (e.g., meters and seconds) before performing calculations!