Math Problem Statement

What type of discontinuity is at x=0

What type of discontinuity is at x=0?

Solution

The graph shows a discontinuity at x=0x = 0. Let us determine the type of discontinuity by analyzing the graph:

  1. At x=0x = 0, the function has a jump discontinuity. This is because:
    • The left-hand limit (limx0f(x)\lim_{x \to 0^-} f(x)) is 2.
    • The right-hand limit (limx0+f(x)\lim_{x \to 0^+} f(x)) is -3.
    • The limits do not match, so there is no continuity at x=0x = 0.

Conclusion:

The discontinuity at x=0x = 0 is a jump discontinuity.

Would you like a more detailed explanation or have further questions?


Here are 5 related questions to explore:

  1. What are the other types of discontinuities, and how do they differ from a jump discontinuity?
  2. How do you calculate the left-hand and right-hand limits of a piecewise function algebraically?
  3. Can a function be integrable if it has jump discontinuities? Why or why not?
  4. How do removable discontinuities appear on a graph?
  5. What is the significance of discontinuities in real-world applications, such as signal processing?

Tip: Always check both the left-hand and right-hand limits to classify discontinuities properly!

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Math Problem Analysis

Mathematical Concepts

Limits and Continuity
Types of Discontinuities
Piecewise Functions

Formulas

Left-hand limit: lim_{x -> c^-} f(x)
Right-hand limit: lim_{x -> c^+} f(x)

Theorems

Definition of Jump Discontinuity

Suitable Grade Level

Grades 10-12