Math Problem Statement
Solution
Let's solve the problem step by step based on the table and the questions given.
Problem Interpretation:
We are given the joint probability distribution for a product's evaluation in two rounds (Round 1: , Round 2: ), where the product is evaluated with ratings of 0, 1, or 2. The product is qualified if it has a rating of 1 or 2, and not qualified if the rating is 0.
Joint Probability Distribution:
The table provides the joint probabilities for and , where is the rating in Round 1 and is the rating in Round 2:
Round 1 (X) \ Round 2 (Y) | 0 | 1 | 2 |
---|---|---|---|
0 | 0.139 | 0.16 | 0.15 |
1 | 0.299 | 0.108 | 0.041 |
2 | 0.054 | 0.014 | 0.035 |
1. Find the probability that the product is evaluated as qualified in both rounds.
The product is qualified in both rounds if and . We sum the joint probabilities where both and are either 1 or 2:
From the table:
2. Find the probability that the product is qualified in the second round given that it is not qualified in the first round.
The product is not qualified in the first round if , and it is qualified in the second round if .
We are looking for:
Where:
Thus:
3. Compute .
The expected value is calculated as the sum of for all possible values of and :
We calculate each term individually using the probabilities from the table:
Simplifying:
Summary of Answers:
- Probability that the product is evaluated as qualified in both rounds: 0.198.
- Probability that the product is qualified in the second round given that it is not qualified in the first round: 0.69.
- : 0.358.
Would you like any further details or clarifications?
Here are some related questions:
- How would the probabilities change if a new joint probability table was given?
- What if the qualifications were based on different thresholds?
- How would you compute or based on the same table?
- How does conditional probability work in more complex joint distributions?
- Can we visualize the probabilities using charts or graphs?
Tip: Always verify that the probabilities in a joint distribution sum to 1 as a consistency check!
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Math Problem Analysis
Mathematical Concepts
Probability
Joint Probability Distribution
Conditional Probability
Expected Value
Formulas
P(Qualified in both rounds) = P(X=1, Y=1) + P(X=1, Y=2) + P(X=2, Y=1) + P(X=2, Y=2)
Conditional Probability: P(B|A) = P(A and B) / P(A)
Expected Value: E(XY) = Σ(X * Y * P(X, Y))
Theorems
Law of Total Probability
Definition of Expected Value
Suitable Grade Level
Grades 11-12, College Level
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