Joe walks 4 meters east, 2 meters south, 4 meters west en finally 2 meters north. What is his displacement vector and the distance he travelled?

To find Joe's displacement vector and the distance he traveled, let's break down his movements:

1. **Distance traveled:**
   - 4 meters east
   - 2 meters south
   - 4 meters west
   - 2 meters north

Total distance = \(4 + 2 + 4 + 2 = 12\) meters.

2. **Displacement vector:**
   - Start at the origin (0,0).
   - After walking 4 meters east: (4, 0)
   - Then 2 meters south: (4, -2)
   - Next, 4 meters west: (0, -2)
   - Finally, 2 meters north: (0, 0)

The final position is (0, 0), which is the same as the starting point. Therefore, the displacement vector is \( (0, 0) \).

**Summary:**
- Total distance traveled: 12 meters
- Displacement vector: \( (0, 0) \)

Do you want more details or have any questions? Here are some related questions to consider:

1. How would the displacement change if he walked in a different order?
2. What is the significance of displacement being zero in this scenario?
3. How would you calculate the resultant vector if he walked additional distances?
4. Can you explain how to visualize this movement on a graph?
5. What is the difference between distance and displacement conceptually?

**Tip:** Always visualize the movements on a coordinate system to better understand displacement.

Discover how to calculate Joe's displacement vector and total distance traveled when he walks in various directions. This problem involves basic concepts of distance and displacement, with a total distance of 12 meters and a displacement vector of (0, 0). Ideal for students in Grades 5-7.

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