Math Problem Statement

%Eff= (1- Tc/Th)x100%, isolate Tc

Solution

To isolate TcT_c (the cold temperature) from the efficiency formula:

%Eff=(1TcTh)×100%\% \text{Eff} = \left( 1 - \frac{T_c}{T_h} \right) \times 100\%

Steps to isolate TcT_c:

  1. Divide both sides by 100 to remove the percentage: %Eff100=1TcTh\frac{\% \text{Eff}}{100} = 1 - \frac{T_c}{T_h}

  2. Subtract 1 from both sides: %Eff1001=TcTh\frac{\% \text{Eff}}{100} - 1 = - \frac{T_c}{T_h}

  3. Multiply both sides by -1 to get rid of the negative sign: 1%Eff100=TcTh1 - \frac{\% \text{Eff}}{100} = \frac{T_c}{T_h}

  4. Multiply both sides by ThT_h to isolate TcT_c: Tc=Th×(1%Eff100)T_c = T_h \times \left( 1 - \frac{\% \text{Eff}}{100} \right)

Thus, the isolated formula for TcT_c is:

Tc=Th×(1%Eff100)T_c = T_h \times \left( 1 - \frac{\% \text{Eff}}{100} \right)

Do you need any further clarification or details?

Here are 5 related questions to consider:

  1. How does the efficiency of a heat engine depend on the temperature difference?
  2. What would happen to the efficiency if ThT_h and TcT_c were very close?
  3. How does an increase in ThT_h affect the value of TcT_c?
  4. Can the efficiency ever be 100% according to this formula?
  5. How does this formula relate to Carnot's theorem?

Tip: Efficiency formulas often assume absolute temperature in Kelvin for accurate calculations, so ensure you use the right units!

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Math Problem Analysis

Mathematical Concepts

Algebra
Equations
Percentage Calculations

Formulas

Efficiency formula: % Eff = (1 - T_c / T_h) * 100%

Theorems

-

Suitable Grade Level

Advanced High School