Is (1,5) a solution to the inequality y<2x+3?

To check if \((1, 5)\) is a solution to the inequality \( y < 2x + 3 \), we substitute \( x = 1 \) and \( y = 5 \) into the inequality and see if it holds true.

The inequality is:
\[
y < 2x + 3
\]

Substituting \( x = 1 \) into the expression on the right-hand side:
\[
2(1) + 3 = 2 + 3 = 5
\]

Now compare \( y = 5 \) to the right-hand side:
\[
5 < 5
\]

This statement is **false** because \( 5 \) is not less than \( 5 \).

Thus, \((1, 5)\) is **not** a solution to the inequality \( y < 2x + 3 \).

Would you like more details or have any other questions?

Here are some related questions:
1. How do you graph inequalities like \( y < 2x + 3 \)?
2. What is the difference between a solution to an equation and a solution to an inequality?
3. How do you find the solution set for an inequality with two variables?
4. What does the graph of \( y = 2x + 3 \) look like?
5. Can inequalities have infinitely many solutions?

**Tip:** When testing a point in an inequality, substitute the values directly into the inequality and carefully check whether the statement holds true.

Is (1,5) a solution to the inequality y < 2x + 3?

Find out whether the point (1,5) satisfies the linear inequality y < 2x + 3. This step-by-step solution walks you through the substitution process and explains why (1,5) is not a solution. Perfect for students in Grades 6-8 studying linear inequalities.

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