Math Problem Statement

7 Let A= [ajl22, where aj 0 for all i,j and A2 = 1. Let a be the sum of all diagonal elements of A and b = |A|. Then 3a? + 4b is equal to

Solution

To solve this problem, let's break it down and analyze the given conditions step by step:

Given:

  1. Matrix A=[aij]R2×2A = [a_{ij}] \in \mathbb{R}^{2 \times 2}, where aij0a_{ij} \geq 0 for all i,ji, j.
  2. Matrix A2=IA^2 = I, where II is the identity matrix (1001)\begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}.
  3. aa is the sum of all diagonal elements of AA, i.e., a=tr(A)a = \text{tr}(A), where tr(A)\text{tr}(A) denotes the trace of AA.
  4. b=Ab = |A|, where A|A| denotes the determinant of AA.
  5. We need to find the value of 3a2+4b3a^2 + 4b.

Step-by-Step Solution:

  1. Matrix Property: Since AA is a 2×22 \times 2 matrix and satisfies A2=IA^2 = I, this means that AA is an involutory matrix (i.e., a matrix such that A2=IA^2 = I).

  2. Structure of AA: For a 2×22 \times 2 matrix AA, let’s assume: A=(a11a12a21a22).A = \begin{pmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \end{pmatrix}. The condition A2=IA^2 = I translates into: (a11a12a21a22)2=(1001).\begin{pmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \end{pmatrix}^2 = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}. Expanding this matrix multiplication yields two conditions:

    • a112+a12a21=1a_{11}^2 + a_{12}a_{21} = 1
    • a222+a12a21=1a_{22}^2 + a_{12}a_{21} = 1
    • a11a12+a12a22=0a_{11}a_{12} + a_{12}a_{22} = 0
    • a21a11+a21a22=0a_{21}a_{11} + a_{21}a_{22} = 0
  3. Trace and Determinant:

    • The trace of AA (sum of diagonal elements): a=a11+a22.a = a_{11} + a_{22}.
    • The determinant of AA: b=det(A)=a11a22a12a21.b = \det(A) = a_{11}a_{22} - a_{12}a_{21}.
  4. Using the Relation A2=IA^2 = I:

    • From the condition a112+a12a21=1a_{11}^2 + a_{12}a_{21} = 1 and a222+a12a21=1a_{22}^2 + a_{12}a_{21} = 1, we get: a112=a222.a_{11}^2 = a_{22}^2. This implies a11=a22a_{11} = a_{22} or a11=a22a_{11} = -a_{22}.
    • If a11=a22a_{11} = a_{22}, then a=a11+a11=2a11a = a_{11} + a_{11} = 2a_{11}.
    • If a11=a22a_{11} = -a_{22}, then a=a11a11=0a = a_{11} - a_{11} = 0.
  5. Possible Values for aa:

    • If a11=a22a_{11} = a_{22}, a=2a11a = 2a_{11}, and since a12a210a_{12}a_{21} \geq 0, b=a112a12a21=1a12a210b = a_{11}^2 - a_{12}a_{21} = 1 - a_{12}a_{21} \geq 0.
    • If a=0a = 0, then b=a12a21=1b = -a_{12}a_{21} = 1.
  6. Computing 3a2+4b3a^2 + 4b:

    • If a=0a = 0 and b=1b = 1: 3a2+4b=3(0)2+4(1)=4.3a^2 + 4b = 3(0)^2 + 4(1) = 4.
    • If a=2a = 2 (for a11=a22=1a_{11} = a_{22} = 1), then b=0b = 0: 3a2+4b=3(2)2+4(0)=3×4=12.3a^2 + 4b = 3(2)^2 + 4(0) = 3 \times 4 = 12.

Since the problem states to find 3a2+4b3a^2 + 4b, the possible values are 4 and 12 depending on the structure of AA. Usually, without additional restrictions, we consider both cases.

Would you like more details on the derivation, or do you have any further questions?

Related Questions:

  1. What is an involutory matrix, and why is it important in this problem?
  2. How do you compute the trace and determinant of a 2×22 \times 2 matrix?
  3. What other types of matrices satisfy the property A2=IA^2 = I?
  4. How does the trace of a matrix relate to its eigenvalues?
  5. What are the conditions for a matrix to have non-negative entries?

Tip:

When dealing with matrices that satisfy specific properties (like A2=IA^2 = I), always try to explore potential forms or values for diagonal and off-diagonal elements to simplify the problem.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Matrix Theory
Involutory Matrices

Formulas

Trace of a matrix: tr(A) = sum of diagonal elements
Determinant of a 2x2 matrix: |A| = a_11 * a_22 - a_12 * a_21
Involutory matrix property: A^2 = I

Theorems

Involutory Matrix Theorem
Determinant Theorem

Suitable Grade Level

Undergraduate (Linear Algebra Level)