Math Problem Statement
A person invests a total of $5,000 in two accounts. One account earns 5% interest, and the other earns 8% interest. At the end of the year, the total interest from both accounts is $340. How much was invested in each account? $2,000 invested at 5%, and $3,000 at 8%
Solution
To solve this problem, we set up a system of equations based on the information provided:
Let:
- = amount invested at 5%
- = amount invested at 8%
We know:
- The total investment is $5,000:
- The total interest earned from both accounts is $340:
Solving the System of Equations
Step 1: Solve for in terms of using the first equation
From :
Step 2: Substitute into the second equation
Substitute into :
Expanding and simplifying:
Step 3: Substitute back into
Solution
- : $2,000 was invested at 5%
- : $3,000 was invested at 8%
This matches the solution you provided.
Would you like a detailed breakdown of the steps?
Related questions:
- What would the investments be if the total interest was different?
- How does changing the interest rates affect the amounts invested?
- What happens if the total investment is altered but interest rates remain the same?
- Can we solve similar problems with different percentages?
- How would the approach change if one interest rate was compounded?
Tip: Setting up equations based on given information is essential for solving investment problems effectively.
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Math Problem Analysis
Mathematical Concepts
Algebra
Linear Equations
System of Equations
Formulas
x + y = Total Investment
Interest Equation: Interest1 + Interest2 = Total Interest
Theorems
Substitution method for solving systems of linear equations
Suitable Grade Level
Grades 8-10
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