Q invested 25% less than what R invested. Also P invested 20% more than what Q invested. What is investment of R if total investment done was Rs 3710.

Let's define the investments of P, Q, and R:

- Let \( R \)'s investment be \( x \).
- Q invested 25% less than R, so Q's investment is \( 0.75x \).
- P invested 20% more than Q, so P's investment is \( 1.2 \times 0.75x = 0.9x \).

The total investment is the sum of P's, Q's, and R's investments, which is given as Rs 3710. Therefore, we have the equation:

\[
P + Q + R = 3710
\]

Substitute the expressions for P, Q, and R:

\[
0.9x + 0.75x + x = 3710
\]

Simplify the equation:

\[
2.65x = 3710
\]

Solve for \( x \):

\[
x = \frac{3710}{2.65} = 1400
\]

Thus, R's investment is Rs 1400.

Would you like further details on any step?

Here are some related questions for practice:

1. If Q had invested 30% less than R, what would the total investment have been?
2. How would the total investment change if P invested 10% more than R?
3. What is Q's investment in the original problem?
4. What percentage of the total investment is R's contribution?
5. If the total investment was Rs 4000, how much would R have invested?

**Tip**: When comparing investments or quantities involving percentages, it's helpful to define variables and express each relationship as an equation.

Q invested 25% less than what R invested. Also, P invested 20% more than what Q invested. What is the investment of R if the total investment done was Rs 3710?

Learn how to solve an investment problem where Q invests 25% less than R, and P invests 20% more than Q, with a total investment of Rs 3710. This problem covers concepts of percentages and algebraic equations, suitable for students in Grades 8-10.

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