Math Problem Statement

Which of the following is the inverse of y=(x−3)3y=(x−3)3?

A.y=x−3−−−−−√3y=x−33

B.y=x+3−−−−−√3y=x+33

C.y=x−−√3−3y=x3−3

D.y=x−−√3+3y=x3+3

Solution

To find the inverse of the function y=(x3)3y = (x - 3)^3, follow these steps:

  1. Start with the given function:
    y=(x3)3y = (x - 3)^3

  2. Swap xx and yy to express the inverse function: x=(y3)3x = (y - 3)^3

  3. Solve for yy. First, take the cube root of both sides: x3=y3\sqrt[3]{x} = y - 3

  4. Add 3 to both sides: y=x3+3y = \sqrt[3]{x} + 3

Thus, the inverse function is: y=x3+3y = \sqrt[3]{x} + 3

Looking at the options provided, the correct answer is:

D. y=x3+3y = \sqrt[3]{x} + 3

Would you like further details or clarifications?

5 Related Questions:

  1. How can you verify that two functions are inverses of each other?
  2. What is the graphical relationship between a function and its inverse?
  3. How do you find the inverse of a more complex function, such as y=(x+5)4y = (x + 5)^4?
  4. What are the restrictions for a function to have an inverse?
  5. How does the derivative of a function relate to the derivative of its inverse?

Tip: When finding the inverse of a function, always remember to swap xx and yy, then solve for yy.

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Math Problem Analysis

Mathematical Concepts

Inverse Functions
Algebra
Cube Roots

Formulas

y = (x - 3)^3
y = ³√x + 3

Theorems

Inverse Function Theorem

Suitable Grade Level

Grades 9-11