Math Problem Statement

solve

The function f is one-to-one. Find its inverse: f(x) = (x + 2)^3 - 8

Solution

We are asked to find the inverse of the given function:

f(x)=(x+2)38f(x) = (x + 2)^3 - 8

Steps to Find the Inverse:

  1. Replace f(x)f(x) with yy: y=(x+2)38y = (x + 2)^3 - 8

  2. Swap xx and yy (this step begins the process of finding the inverse): x=(y+2)38x = (y + 2)^3 - 8

  3. Solve for yy:

    • Add 8 to both sides: x+8=(y+2)3x + 8 = (y + 2)^3
    • Take the cube root of both sides: x+83=y+2\sqrt[3]{x + 8} = y + 2
    • Subtract 2 from both sides: y=x+832y = \sqrt[3]{x + 8} - 2

Thus, the inverse function is:

f1(x)=x+832f^{-1}(x) = \sqrt[3]{x + 8} - 2

Would you like more details on how to verify this result or further clarification on the steps?

Related Questions:

  1. What does it mean for a function to be "one-to-one"?
  2. How can you verify that two functions are inverses of each other?
  3. What is the domain of the inverse function f1(x)f^{-1}(x)?
  4. How do transformations affect the graph of a cubic function?
  5. Can a function have more than one inverse?

Tip:

Always check if the function is one-to-one by verifying that it passes the horizontal line test; this ensures the function has an inverse.

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Math Problem Analysis

Mathematical Concepts

Functions
Inverse Functions
Cubic Functions

Formulas

Inverse function: f^{-1}(x)
Cube root function: \sqrt[3]{x}

Theorems

One-to-one function
Horizontal line test

Suitable Grade Level

Grades 10-12