Math Problem Statement
Solution
Let's solve the problem of finding the inverse for each matrix.
Part a)
Matrix:
For a matrix , the inverse exists if the determinant , and the inverse is given by:
Here, , , , and .
- The determinant: .
- Since , the inverse exists.
The inverse is:
Part b)
Matrix:
- The determinant: .
Since , the matrix does not have an inverse.
Part c)
Matrix:
To find the inverse of a matrix, we need to compute the determinant and use cofactor expansion or row reduction. I will skip the detailed expansion here, but the process involves computing the determinant (using cofactor expansion), checking if it's non-zero, and then finding the adjugate matrix and dividing it by the determinant.
- The determinant of this matrix is non-zero, so it has an inverse.
- The inverse can be calculated, but given the complexity, I will write down the final result.
The inverse is:
Part d)
Matrix:
- The determinant: (You can expand along the first row to verify this).
Since , the matrix does not have an inverse.
Summary:
- a) Inverse exists:
- b) No inverse.
- c) Inverse exists:
- d) No inverse.
Would you like to dive into any details or have any questions?
Here are 5 related questions for further practice:
- How do you find the determinant of a 3x3 matrix?
- Why does a matrix with a zero determinant not have an inverse?
- How is cofactor expansion used to find the determinant of larger matrices?
- Can every square matrix be inverted? If not, why?
- How can matrix inverses be used in solving systems of equations?
Tip: If you're unsure whether a matrix has an inverse, checking the determinant is the quickest first step!
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Math Problem Analysis
Mathematical Concepts
Matrix algebra
Determinants
Inverse of matrices
Formulas
For a 2x2 matrix A = [a b; c d], the inverse exists if det(A) = ad - bc ≠ 0, and A^{-1} = (1/det(A)) * [d -b; -c a]
For larger matrices (3x3), determinants are calculated using cofactor expansion, and the inverse is found using the adjugate matrix method.
Theorems
Inverse of matrices exists if determinant ≠ 0
Suitable Grade Level
Grades 10-12, University
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