Math Problem Statement

For the function f(x) = ⁵√x + 1, find f⁻¹(x).

Solution

To find the inverse of the function f(x)=x5+1f(x) = \sqrt[5]{x} + 1, we can follow these steps:

  1. Rewrite the function: Start by setting y=f(x)y = f(x). y=x5+1y = \sqrt[5]{x} + 1

  2. Isolate the radical: Subtract 1 from both sides to isolate the fifth root. y1=x5y - 1 = \sqrt[5]{x}

  3. Remove the radical: Raise both sides to the power of 5 to eliminate the root. (y1)5=x(y - 1)^5 = x

  4. Solve for xx: Since y=f(x)y = f(x), the inverse function f1(x)f^{-1}(x) will switch the roles of xx and yy. f1(x)=(x1)5f^{-1}(x) = (x - 1)^5

So, the correct answer is:

f1(x)=(x1)5f^{-1}(x) = (x - 1)^5

This matches the first option provided in the image.

Would you like any further details or explanations on how this works?

Relative Questions:

  1. How do you generally find the inverse of a function?
  2. What are the conditions under which a function has an inverse?
  3. How can you verify that two functions are indeed inverses of each other?
  4. What is the significance of one-to-one functions in finding inverses?
  5. How does the domain and range of a function relate to its inverse?

Tip:

When finding the inverse of a function, it's often helpful to check the original function and its inverse by composing them, i.e., check that f(f1(x))=xf(f^{-1}(x)) = x and f1(f(x))=xf^{-1}(f(x)) = x.

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Math Problem Analysis

Mathematical Concepts

Inverse Functions
Radical Expressions

Formulas

(y - 1)^5 = x
f⁻¹(x) = (x - 1)^5

Theorems

Inverse Function Theorem

Suitable Grade Level

Grades 10-12