Math Problem Statement

Let f(x)=1/x+4

what does f^-1(x)=

Solution

To find the inverse of the function f(x)=1x+4f(x) = \frac{1}{x} + 4, we need to follow these steps:

  1. Replace f(x)f(x) with yy: y=1x+4y = \frac{1}{x} + 4

  2. Swap xx and yy to solve for the inverse: x=1y+4x = \frac{1}{y} + 4

  3. Solve for yy: x4=1yx - 4 = \frac{1}{y} y=1x4y = \frac{1}{x - 4}

So, the inverse function is: f1(x)=1x4f^{-1}(x) = \frac{1}{x - 4}

Would you like more details or have any questions?

Here are 5 related questions to expand on this concept:

  1. How do you verify that f(f1(x))=xf(f^{-1}(x)) = x?
  2. What is the domain and range of f1(x)=1x4f^{-1}(x) = \frac{1}{x - 4}?
  3. How do you find the inverse of a more complicated rational function?
  4. Can all functions have an inverse? If not, why?
  5. How do transformations (like shifting or scaling) affect the inverse of a function?

Tip: The domain of an inverse function is the range of the original function, and vice versa. Keep this in mind when solving inverse problems!

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Math Problem Analysis

Mathematical Concepts

Inverse Functions
Algebra
Rational Functions

Formulas

f(x) = 1/x + 4
f^{-1}(x) = 1/(x - 4)

Theorems

Inverse Function Theorem

Suitable Grade Level

Grades 10-12