Math Problem Statement

f^-1(x) = cuberoot x-9

Substitute the definition of​ f(x): f(f^-1(x))= f() = x^3+9 Substitute the definition of​ f^-1(x): f^-1() = x

Solution

We are given the inverse function f1(x)=x39f^{-1}(x) = \sqrt[3]{x} - 9, and we are also asked to find the function f(x)f(x), such that:

  • f(f1(x))=xf(f^{-1}(x)) = x
  • f1(f(x))=xf^{-1}(f(x)) = x

Step 1: Define the function f(x)f(x)

We are given f1(x)=x39f^{-1}(x) = \sqrt[3]{x} - 9. To find f(x)f(x), we need to reverse the operations done by f1(x)f^{-1}(x).

Starting with: f1(x)=x39f^{-1}(x) = \sqrt[3]{x} - 9

To isolate xx, add 9 to both sides: f1(x)+9=x3f^{-1}(x) + 9 = \sqrt[3]{x}

Now, cube both sides to undo the cube root: (f1(x)+9)3=x(f^{-1}(x) + 9)^3 = x

This implies that f(x)=(x+9)3f(x) = (x + 9)^3.

Step 2: Verify by substitution

Verify f(f1(x))=xf(f^{-1}(x)) = x

We substitute f1(x)f^{-1}(x) into f(x)f(x): f(f1(x))=((x39)+9)3f(f^{-1}(x)) = \left( \left( \sqrt[3]{x} - 9 \right) + 9 \right)^3 Simplifying: f(f1(x))=(x3)3=xf(f^{-1}(x)) = (\sqrt[3]{x})^3 = x

Thus, f(f1(x))=xf(f^{-1}(x)) = x, as required.

Verify f1(f(x))=xf^{-1}(f(x)) = x

Now, we substitute f(x)f(x) into f1(x)f^{-1}(x): f1(f(x))=(x+9)339f^{-1}(f(x)) = \sqrt[3]{(x + 9)^3} - 9 Simplifying: f1(f(x))=x+99=xf^{-1}(f(x)) = x + 9 - 9 = x

Thus, f1(f(x))=xf^{-1}(f(x)) = x, as required.

Final Answer:

The function f(x)f(x) is f(x)=(x+9)3f(x) = (x + 9)^3, and the inverse is f1(x)=x39f^{-1}(x) = \sqrt[3]{x} - 9.

Would you like more details on any step?

Related Questions:

  1. How do you compute the inverse of a general cubic function?
  2. What are the general properties of inverse functions?
  3. How can you verify if two functions are inverses of each other?
  4. What transformations are involved in the function f(x)=(x+9)3f(x) = (x + 9)^3?
  5. How do cube roots work in solving equations?

Tip: When working with inverse functions, always verify by checking f(f1(x))=xf(f^{-1}(x)) = x and f1(f(x))=xf^{-1}(f(x)) = x.

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Math Problem Analysis

Mathematical Concepts

Inverse Functions
Cubic Functions
Algebra

Formulas

f^{-1}(x) = \sqrt[3]{x} - 9
f(x) = (x + 9)^3
f(f^{-1}(x)) = x
f^{-1}(f(x)) = x

Theorems

Inverse Function Theorem

Suitable Grade Level

Grades 10-12