Math Problem Statement

The graph shows y = csc(x). Which of the following is true of its inverse? Check all that apply.

Solution

The graph shown represents the function y=csc(x)y = \csc(x), which is the reciprocal of the sine function, i.e., csc(x)=1sin(x)\csc(x) = \frac{1}{\sin(x)}. The graph has vertical asymptotes wherever the sine function is zero, which occurs at multiples of π\pi, such as x=2π,π,0,π,2πx = -2\pi, -\pi, 0, \pi, 2\pi, etc.

Now, you are asked to determine certain properties about the inverse of y=csc(x)y = \csc(x), that is, y=\arccsc(x)y = \arccsc(x). Let's evaluate each of the options:

1. Zeros: None

The cosecant function csc(x)\csc(x) has no zeros because the sine function is never zero for the values where cosecant is defined (it is undefined at the zeros of sine). Since the inverse function y=\arccsc(x)y = \arccsc(x) would also be undefined at zero, there are no zeros. This statement is true.

2. Domain: (,1][1,)(-\infty, -1] \cup [1, \infty)

The domain of the inverse cosecant function is where the original function csc(x)\csc(x) takes its values. Since csc(x)\csc(x) is undefined between -1 and 1 (because sine never reaches those values), the domain of the inverse is (,1][1,)(-\infty, -1] \cup [1, \infty). This statement is true.

3. Range: [0,π][0, \pi]

The range of \arccsc(x)\arccsc(x) corresponds to the possible angles that yield values within the domain of the cosecant function. For y=\arccsc(x)y = \arccsc(x), we are typically concerned with angles in the range [π2,π2][-\frac{\pi}{2}, \frac{\pi}{2}] for the principal value. This statement is false, as the range is usually [π2,π2][-\frac{\pi}{2}, \frac{\pi}{2}], excluding zero.

4. Minimum: π2-\frac{\pi}{2}

The minimum value for the inverse cosecant function occurs when x=x = -\infty, which approaches π2-\frac{\pi}{2}. This statement is true.

5. Maximum: π2\frac{\pi}{2}

The maximum value for the inverse cosecant function occurs when x=x = \infty, which corresponds to π2\frac{\pi}{2}. This statement is true.

6. Increasing on (π2,π)\left( \frac{\pi}{2}, \pi \right) and (π,3π2)\left( \pi, \frac{3\pi}{2} \right)

The inverse cosecant function is decreasing overall because cosecant decreases as you move along the positive or negative directions from its vertical asymptotes. This statement is false, as the inverse function should not be increasing on these intervals.

Summary of Correct Statements:

  • Zeros: None (True)
  • Domain: (,1][1,)(-\infty, -1] \cup [1, \infty) (True)
  • Minimum: π2-\frac{\pi}{2} (True)
  • Maximum: π2\frac{\pi}{2} (True)

Would you like further details on any part of the explanation? Here are five related questions to help you explore this topic:

  1. What is the difference between the graph of y=csc(x)y = \csc(x) and y=sin(x)y = \sin(x)?
  2. How does the range of \arccsc(x)\arccsc(x) compare to other inverse trigonometric functions like arcsin(x)\arcsin(x)?
  3. Why does csc(x)\csc(x) have vertical asymptotes?
  4. Can we define csc(x)\csc(x) for values between 1-1 and 11?
  5. What are the properties of the graph of y=\arccsc(x)y = \arccsc(x)?

Tip: When working with inverse functions, always pay attention to both the domain and range of the original function, as they swap roles in the inverse.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Inverse Trigonometric Functions
Cosecant Function
Asymptotes
Domain and Range

Formulas

csc(x) = 1/sin(x)
Inverse: y = arccsc(x)

Theorems

Properties of Inverse Functions
Domain and Range of Cosecant and Arccosecant

Suitable Grade Level

Grades 10-12