Math Problem Statement

((10x)^n/(n^5)) interval of convergence and radius

Solution

To determine the interval of convergence and radius of convergence for the series

n=1(10x)nn5,\sum_{n=1}^{\infty} \frac{(10x)^n}{n^5},

we use the ratio test.


1. Apply the Ratio Test

The ratio test examines the limit of consecutive terms: L=limnan+1an.L = \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right|. Here, an=(10x)nn5a_n = \frac{(10x)^n}{n^5}. So: an+1=(10x)n+1(n+1)5.a_{n+1} = \frac{(10x)^{n+1}}{(n+1)^5}.

The ratio becomes: an+1an=(10x)n+1(n+1)5n5(10x)n=10xn5(n+1)5.\left| \frac{a_{n+1}}{a_n} \right| = \left| \frac{(10x)^{n+1}}{(n+1)^5} \cdot \frac{n^5}{(10x)^n} \right| = \left| \frac{10x \cdot n^5}{(n+1)^5} \right|.

Simplify: an+1an=10xn5(n+1)5.\left| \frac{a_{n+1}}{a_n} \right| = |10x| \cdot \frac{n^5}{(n+1)^5}.


2. Evaluate the Limit

As nn \to \infty, n5(n+1)51.\frac{n^5}{(n+1)^5} \to 1.

Thus: L=limnan+1an=10x1=10x.L = \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| = |10x| \cdot 1 = |10x|.

For convergence, the ratio test requires: L<1    10x<1    x<110.L < 1 \implies |10x| < 1 \implies |x| < \frac{1}{10}.


3. Determine the Interval and Radius of Convergence

  • Radius of Convergence: R=110R = \frac{1}{10}.
  • Interval of Convergence: x<110|x| < \frac{1}{10} implies x(110,110)x \in \left(-\frac{1}{10}, \frac{1}{10}\right).

4. Check the Endpoints

To find the exact interval, we need to check x=±110x = \pm \frac{1}{10}.

At x=110x = \frac{1}{10}:

The series becomes: n=1(10110)nn5=n=11n5.\sum_{n=1}^\infty \frac{(10 \cdot \frac{1}{10})^n}{n^5} = \sum_{n=1}^\infty \frac{1}{n^5}. This is a pp-series with p=5>1p = 5 > 1, which converges.

At x=110x = -\frac{1}{10}:

The series becomes: n=1(10110)nn5=n=1(1)nn5.\sum_{n=1}^\infty \frac{(10 \cdot -\frac{1}{10})^n}{n^5} = \sum_{n=1}^\infty \frac{(-1)^n}{n^5}. This is an alternating pp-series with p=5>1p = 5 > 1, which converges.


Final Answer

  • Interval of Convergence: [110,110]\left[ -\frac{1}{10}, \frac{1}{10} \right].
  • Radius of Convergence: R=110R = \frac{1}{10}.

Do you want further details or have any questions? Here are five related questions:

  1. How does the ratio test work for different series?
  2. Can you explain the pp-series test for convergence?
  3. What happens if p<1p < 1 in a pp-series?
  4. How do alternating series tests determine convergence?
  5. How do we interpret the radius and interval of convergence practically?

Tip: Always check the endpoints separately when determining the interval of convergence, as they often behave differently than the interior points.

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Math Problem Analysis

Mathematical Concepts

Series Convergence
Interval of Convergence
Radius of Convergence
Ratio Test
p-Series

Formulas

Ratio Test: L = lim (n → ∞) |a_{n+1} / a_n|
p-Series: Σ(1/n^p) converges if p > 1
Condition for Convergence: |x| < R (Radius of Convergence)

Theorems

Ratio Test
p-Series Test
Alternating Series Test

Suitable Grade Level

Grades 11-12 and College Level