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We are given the series

\[
\sum_{k=0}^{\infty} \frac{3^k (x - 4)^k}{k}
\]

and asked to find its interval of convergence.

### Step 1: Apply the Ratio Test
To find the interval of convergence, we use the **Ratio Test** for the general term \( a_k = \frac{3^k (x - 4)^k}{k} \). According to the ratio test, for a series \( \sum a_k \), the radius of convergence \( R \) can be determined by checking the limit:

\[
L = \lim_{k \to \infty} \left| \frac{a_{k+1}}{a_k} \right|.
\]

We will now compute \( L \) for the given series.

### Step 2: Compute the Ratio \( \left| \frac{a_{k+1}}{a_k} \right| \)

First, write the terms \( a_{k+1} \) and \( a_k \):
- \( a_k = \frac{3^k (x - 4)^k}{k} \),
- \( a_{k+1} = \frac{3^{k+1} (x - 4)^{k+1}}{k+1} = \frac{3 \cdot 3^k (x - 4) \cdot (x - 4)^k}{k+1} \).

Now, take the ratio:

\[
\frac{a_{k+1}}{a_k} = \frac{\frac{3 \cdot 3^k (x - 4) \cdot (x - 4)^k}{k+1}}{\frac{3^k (x - 4)^k}{k}} = \frac{3(x - 4)}{1} \cdot \frac{k}{k+1}.
\]

Simplifying this:

\[
\left| \frac{a_{k+1}}{a_k} \right| = 3 |x - 4| \cdot \frac{k}{k+1}.
\]

As \( k \to \infty \), \( \frac{k}{k+1} \to 1 \), so we have:

\[
L = \lim_{k \to \infty} \left| \frac{a_{k+1}}{a_k} \right| = 3 |x - 4|.
\]

### Step 3: Apply the Ratio Test Condition
The Ratio Test states that the series converges when \( L < 1 \). Thus, we require:

\[
3 |x - 4| < 1.
\]

Dividing both sides by 3:

\[
|x - 4| < \frac{1}{3}.
\]

### Step 4: Solve for the Interval of Convergence
This inequality means that \( x \) must lie within \( \frac{1}{3} \) units of 4. Therefore, the interval is:

\[
4 - \frac{1}{3} < x < 4 + \frac{1}{3},
\]

or equivalently:

\[
\frac{11}{3} < x < \frac{13}{3}.
\]

### Step 5: Check the Endpoints
To determine if the endpoints \( x = \frac{11}{3} \) and \( x = \frac{13}{3} \) are included in the interval, we substitute these values into the series and check for convergence.

- At \( x = \frac{11}{3} \), the series becomes a harmonic series, which **diverges**.
- At \( x = \frac{13}{3} \), the series again becomes harmonic, and it **diverges**.

Thus, the endpoints are not included in the interval.

### Final Answer: 
The interval of convergence is:

\[
\left( \frac{11}{3}, \frac{13}{3} \right).
\]

Would you like a more detailed explanation of any part, or have any further questions?

Here are 5 related questions to explore this topic further:
1. How do you check convergence at endpoints using other convergence tests?
2. What happens if the Ratio Test gives a limit equal to 1?
3. How does the Ratio Test work for other types of series, like alternating series?
4. What is the difference between absolute and conditional convergence?
5. How can power series be applied in approximating functions?

**Tip:** For any power series, always test both endpoints to ensure whether they are included in the interval of convergence!

Determine interval of convergence for the series: ∑ (3^k(x - 4)^k) / k.

Learn how to determine the interval of convergence for the series involving the ratio test. This detailed solution includes using the ratio test for the power series ∑ (3^k(x - 4)^k) / k and checking for convergence at the endpoints.

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