Math Problem Statement

A small radio transmitter broadcasts in a 60 mile radius. If you drive along a straight line from a city 80 miles north of the transmitter to a second city 73 miles east of the transmitter, during how much of the drive will you pick up a signal from the transmitter?

Solution

To determine how much of the drive you'll receive the signal, we must calculate the length of the line segment along which the car is within the 60-mile broadcast radius of the transmitter.


Step 1: Represent the Problem in Coordinate Geometry

We place the transmitter at the origin (0,0)(0, 0). The cities are:

  • The first city is 80 miles north, so it has coordinates (0,80)(0, 80).
  • The second city is 73 miles east, so it has coordinates (73,0)(73, 0).

The line segment representing the drive is the line between (0,80)(0, 80) and (73,0)(73, 0).

The broadcast radius is a circle centered at (0,0)(0, 0) with a radius of 60 miles.


Step 2: Equation of the Line

The equation of the line passing through (0,80)(0, 80) and (73,0)(73, 0) can be found using the slope-intercept form: y=mx+by = mx + b

  • The slope mm is: m=y2y1x2x1=080730=8073.m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 80}{73 - 0} = -\frac{80}{73}.
  • The yy-intercept bb is 80 (since the line passes through (0,80)(0, 80)).

Thus, the equation of the line is: y=8073x+80.y = -\frac{80}{73}x + 80.


Step 3: Intersection with the Circle

The equation of the circle is: x2+y2=602=3600.x^2 + y^2 = 60^2 = 3600.

Substitute y=8073x+80y = -\frac{80}{73}x + 80 into the circle's equation: x2+(8073x+80)2=3600.x^2 + \left(-\frac{80}{73}x + 80\right)^2 = 3600.

Expand the squared term: (8073x+80)2=(8073x)2+2(8073x)(80)+802,\left(-\frac{80}{73}x + 80\right)^2 = \left(-\frac{80}{73}x\right)^2 + 2\left(-\frac{80}{73}x\right)(80) + 80^2, (8073x+80)2=64005329x21280073x+6400.\left(-\frac{80}{73}x + 80\right)^2 = \frac{6400}{5329}x^2 - \frac{12800}{73}x + 6400.

Substitute this back: x2+64005329x21280073x+6400=3600.x^2 + \frac{6400}{5329}x^2 - \frac{12800}{73}x + 6400 = 3600.

Combine like terms: (1+64005329)x21280073x+6400=3600.\left(1 + \frac{6400}{5329}\right)x^2 - \frac{12800}{73}x + 6400 = 3600.

Simplify: 5329+64005329x21280073x+6400=3600.\frac{5329 + 6400}{5329}x^2 - \frac{12800}{73}x + 6400 = 3600. 117295329x21280073x+64003600=0.\frac{11729}{5329}x^2 - \frac{12800}{73}x + 6400 - 3600 = 0. 117295329x21280073x+2800=0.\frac{11729}{5329}x^2 - \frac{12800}{73}x + 2800 = 0.


Step 4: Solve for xx

Multiply through by 5329735329 \cdot 73 to eliminate fractions: (11729)(73)x2(12800)(5329)x+(2800)(5329)(73)=0.(11729)(73)x^2 - (12800)(5329)x + (2800)(5329)(73) = 0.

Solve this quadratic equation for xx, then calculate yy for the corresponding points. The length of the segment within the circle can be found by calculating the distance between the two intersection points.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Algebra
Intersection of Lines and Circles
Distance Calculation

Formulas

Equation of a line: y = mx + b
Equation of a circle: x^2 + y^2 = r^2
Quadratic equation: ax^2 + bx + c = 0
Distance formula: d = √((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Properties of lines and circles in coordinate geometry
Quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a

Suitable Grade Level

Grades 10-12