Math Problem Statement

Integrate using the indicated substitution: ∫ e^2x √(1 - e^2x) dx, with u = 1 - e^2x.

Solution

The given problem asks for the evaluation of the integral:

e2x1e2xdx\int e^{2x} \sqrt{1 - e^{2x}} \, dx with the substitution u=1e2xu = 1 - e^{2x}.

Let's go step by step to solve this:

Step 1: Perform the substitution

We are given u=1e2xu = 1 - e^{2x}. Now, differentiate both sides with respect to xx to find dudu:

du=2e2xdxdu2=e2xdxdu = -2e^{2x} \, dx \quad \Rightarrow \quad \frac{du}{-2} = e^{2x} \, dx

Step 2: Substitute in the integral

Substitute e2xdxe^{2x} \, dx with du2\frac{du}{-2} and 1e2x1 - e^{2x} with uu. The integral becomes:

e2x1e2xdx=udu2\int e^{2x} \sqrt{1 - e^{2x}} \, dx = \int \sqrt{u} \cdot \frac{du}{-2}

Step 3: Simplify the integral

This simplifies to:

12u1/2du-\frac{1}{2} \int u^{1/2} \, du

Step 4: Integrate

Now integrate:

12u1/2du=1223u3/2=13u3/2-\frac{1}{2} \int u^{1/2} \, du = -\frac{1}{2} \cdot \frac{2}{3} u^{3/2} = -\frac{1}{3} u^{3/2}

Step 5: Substitute back uu

Finally, substitute u=1e2xu = 1 - e^{2x} back into the expression:

13(1e2x)3/2+C-\frac{1}{3} \left( 1 - e^{2x} \right)^{3/2} + C

Final Answer:

The solution to the integral is:

13(1e2x)3/2+C-\frac{1}{3} \left( 1 - e^{2x} \right)^{3/2} + C

Would you like further details on any part of this process?


Here are 5 related questions you could explore:

  1. How does substitution simplify complex integrals in general?
  2. Can this method be used for integrals with different exponents in exe^x?
  3. What is the geometric interpretation of an integral like this?
  4. How does integration by substitution compare to other methods like integration by parts?
  5. What are common mistakes to avoid when using substitution in integration?

Tip: Always differentiate your substitution to ensure you accurately replace dxdx in the integral.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Integration
Substitution Method
Exponential Functions

Formulas

u = 1 - e^{2x}
du = -2e^{2x} dx
Integral of u^{1/2}

Theorems

Substitution in Integration

Suitable Grade Level

Undergraduate Calculus (Grades 11-12 or College Level)