Math Problem Statement

Evaluate the integral of e^(2x+3) with respect to x and differentiate y' = (x / (0.5t - 2x))^2.

Solution

I see the image you uploaded contains two mathematical expressions. Let's break them down:

  1. Integral: The first equation appears to be the integral of e2x+3e^{2x+3} with respect to xx. This is an exponential function that we need to integrate.

    The integral of eax+be^{ax+b} (where aa and bb are constants) is given by: eax+bdx=1aeax+b+C\int e^{ax+b} \, dx = \frac{1}{a} e^{ax+b} + C For e2x+3e^{2x+3}, we have a=2a = 2 and b=3b = 3. Thus, the integral becomes: e2x+3dx=12e2x+3+C\int e^{2x+3} \, dx = \frac{1}{2} e^{2x+3} + C

  2. Derivative: The second equation seems to be a derivative. It’s unclear whether yy' is the derivative of a function, but the expression inside looks like a ratio. The expression is: y=x0.5t2xy' = \frac{x}{0.5t - 2x} If this is the derivative of some function, it would typically suggest a rational function where you could apply techniques such as the quotient rule to differentiate.

Would you like me to provide more detailed steps for either part, or do you need help with something else in this image?

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Math Problem Analysis

Mathematical Concepts

Integration
Differentiation
Exponential Functions
Rational Functions

Formulas

∫ e^(ax+b) dx = (1/a) e^(ax+b) + C
Quotient Rule: (f/g)' = (f'g - fg') / g^2

Theorems

Basic Exponential Integration Theorem
Quotient Rule for Differentiation

Suitable Grade Level

Grades 10-12