Math Problem Statement

integrate (x^3 cos (x/2) + 1/2) (4-x^2)^1/2 dx

Solution

To solve the integral (x3cos(x2)+12)4x2dx\int \left( x^3 \cos \left( \frac{x}{2} \right) + \frac{1}{2} \right) \sqrt{4 - x^2} \, dx, we will proceed step by step.

Step 1: Split the Integral

First, break the integral into two parts:

I=(x3cos(x2)+12)4x2dxI = \int \left( x^3 \cos \left( \frac{x}{2} \right) + \frac{1}{2} \right) \sqrt{4 - x^2} \, dx

This can be written as:

I=x3cos(x2)4x2dx+124x2dxI = \int x^3 \cos \left( \frac{x}{2} \right) \sqrt{4 - x^2} \, dx + \int \frac{1}{2} \sqrt{4 - x^2} \, dx

We now handle each term separately.

Step 2: Solve the Second Integral

Start with the simpler term:

124x2dx\int \frac{1}{2} \sqrt{4 - x^2} \, dx

This is a standard integral, and it can be solved by a trigonometric substitution:

Let x=2sinθx = 2 \sin \theta, so that dx=2cosθdθdx = 2 \cos \theta \, d\theta, and 4x2=2cosθ\sqrt{4 - x^2} = 2 \cos \theta. The integral becomes:

122cos2θ2cosθdθ=2cos2θdθ\frac{1}{2} \int 2 \cos^2 \theta \cdot 2 \cos \theta \, d\theta = 2 \int \cos^2 \theta \, d\theta

Now use the identity cos2θ=1+cos(2θ)2\cos^2 \theta = \frac{1 + \cos(2\theta)}{2}:

2cos2θdθ=(1+cos(2θ))dθ2 \int \cos^2 \theta \, d\theta = \int (1 + \cos(2\theta)) \, d\theta

This integrates to:

θ+12sin(2θ)+C\theta + \frac{1}{2} \sin(2\theta) + C

Converting back to xx, recall that θ=arcsin(x2)\theta = \arcsin \left( \frac{x}{2} \right), and we get:

x24x2+C1\frac{x}{2} \sqrt{4 - x^2} + C_1

Step 3: First Integral

Now handle the more complicated term:

x3cos(x2)4x2dx\int x^3 \cos \left( \frac{x}{2} \right) \sqrt{4 - x^2} \, dx

This integral is more challenging and may require advanced techniques such as integration by parts or a series expansion. For now, this can be computed using numerical methods or specialized software for exact solutions, as it does not have a simple closed form.

Step 4: Combine the Results

Thus, the solution to the integral is:

I=x24x2+(solution to the first integral)+CI = \frac{x}{2} \sqrt{4 - x^2} + \text{(solution to the first integral)} + C

Let me know if you'd like help finding the numerical value of the first term or clarifying any step.


Would you like more details or have any questions?
Here are some related problems to explore:

  1. Integrate 4x2dx\int \sqrt{4 - x^2} \, dx.
  2. Solve x2cos(x)dx\int x^2 \cos(x) \, dx.
  3. Compute sin(x)1x2dx\int \sin(x) \sqrt{1 - x^2} \, dx.
  4. Find the integral x3exdx\int x^3 e^x \, dx.
  5. Evaluate x34x2dx\int x^3 \sqrt{4 - x^2} \, dx.

Tip: Breaking a complex integral into smaller parts is often key to finding a solution.

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Math Problem Analysis

Mathematical Concepts

Integration
Trigonometric Substitution
Integration by Parts

Formulas

Trigonometric substitution: x = 2sin(θ)
Integral of cos^2(θ): ∫cos^2(θ) dθ = ∫(1 + cos(2θ))/2 dθ

Theorems

Trigonometric Identities
Integration by Parts

Suitable Grade Level

University Level - Calculus II