Math Problem Statement

selesaikan

Dengan menggunakan substitusi u = 2x + 1, maka integral \( \int_1^3 (2x + 1)^3 \, dx \) akan menjadi \( \int_a^b \frac{u^3}{2} \, du \) dengan \( b-a = \dots \).

Solution

py import symbols, integrate, simplify

Define the variables

x, u = symbols('x u')

Define the substitution

u_sub = 2*x + 1 du_dx = 2 # Derivative of u with respect to x

Integral with substitution

expr = (2x + 1)**3 integral_substituted = expr.subs(2x + 1, u) / du_dx

Simplify the integral expression

integral_result = simplify(integral_substituted)

Compute the limits of integration

a = 2 * 1 + 1 # lower limit when x=1 b = 2 * 3 + 1 # upper limit when x=3 u_limits = (a, b)

integral_result,Using the substitution u=2x+1u = 2x + 1, the integral

13(2x+1)3dx\int_1^3 (2x+1)^3 \, dx

becomes

37u32du,\int_3^7 \frac{u^3}{2} \, du,

where the limits of integration change from x=1x=1 to x=3x=3 to u=3u=3 to u=7u=7. The resulting form is u32\frac{u^3}{2}.

Questions for Further Understanding:

  1. Would you like to calculate the definite integral value for this?
  2. Do you want the integral computed step-by-step for better understanding?
  3. Are there other substitution techniques you’d like to compare this with?
  4. How does the change in limits affect the calculation here?
  5. Would you like examples of similar integral substitutions?

Tip: Always double-check the limits after substitution, as they need to align with the new variable for correctness

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Math Problem Analysis

Mathematical Concepts

Integral substitution
Definite integrals
Limits of integration

Formulas

Substitution: u = 2x + 1
Change of variable: \( dx = \frac{du}{du/dx} \)
Integral transformation

Theorems

Fundamental Theorem of Calculus
Integration by substitution

Suitable Grade Level

Grades 11-12 or College-level Calculus