It looks like you're asking for the integral:

\[
\int \frac{x^2 + 1}{x^2 - 5x + 6} \, dx
\]

Let's solve this step by step.

### Step 1: Factor the Denominator
First, let's factor the quadratic in the denominator:

\[
x^2 - 5x + 6 = (x - 2)(x - 3)
\]

### Step 2: Simplify the Integrand
The integral becomes:

\[
\int \frac{x^2 + 1}{(x - 2)(x - 3)} \, dx
\]

### Step 3: Divide the Numerator
To simplify, let's divide the numerator by the denominator:

We perform polynomial long division by dividing \( x^2 + 1 \) by \( x^2 - 5x + 6 \).

\[
\frac{x^2 + 1}{x^2 - 5x + 6} = 1 + \frac{(5x - 5)}{(x - 2)(x - 3)}
\]

### Step 4: Partial Fraction Decomposition
Now, let's break down \( \frac{5x - 5}{(x - 2)(x - 3)} \) using partial fractions:

\[
\frac{5x - 5}{(x - 2)(x - 3)} = \frac{A}{x - 2} + \frac{B}{x - 3}
\]

To find \( A \) and \( B \):

\[
5x - 5 = A(x - 3) + B(x - 2)
\]

Expanding and collecting terms:

\[
5x - 5 = (A + B)x - (3A + 2B)
\]

Now, equate coefficients of like terms:

1. Coefficient of \( x \): \( A + B = 5 \)
2. Constant term: \( -3A - 2B = -5 \)

### Step 5: Solve for \( A \) and \( B \)
Solve the system of equations:

\[
A + B = 5
\]
\[
-3A - 2B = -5
\]

From the first equation, \( B = 5 - A \). Substituting into the second equation:

\[
-3A - 2(5 - A) = -5
\]
\[
-3A - 10 + 2A = -5
\]
\[
-A = 5 \quad \Rightarrow \quad A = -5
\]
\[
B = 5 - (-5) = 10
\]

Thus:

\[
\frac{5x - 5}{(x - 2)(x - 3)} = \frac{-5}{x - 2} + \frac{10}{x - 3}
\]

### Step 6: Integrate
Now, substitute back into the integral:

\[
\int \frac{x^2 + 1}{(x - 2)(x - 3)} \, dx = \int \left(1 + \frac{-5}{x - 2} + \frac{10}{x - 3}\right) \, dx
\]

This simplifies to:

\[
x - 5 \ln |x - 2| + 10 \ln |x - 3| + C
\]

Where \( C \) is the constant of integration.

### Final Answer:
\[
\int \frac{x^2 + 1}{x^2 - 5x + 6} \, dx = x - 5 \ln |x - 2| + 10 \ln |x - 3| + C
\]

Let me know if you need further explanation or have any other questions!

---

1. What are the basic steps in polynomial long division?
2. How do you approach solving integrals that involve partial fractions?
3. What is the significance of logarithms appearing in the final answer?
4. Can partial fractions always be used when integrating rational functions?
5. How does one determine the constants in partial fraction decomposition?

**Tip:** It's useful to check your integration result by differentiating it to see if you obtain the original integrand.

Learn how to integrate the rational function (x^2 + 1)/(x^2 - 5x + 6) step-by-step with detailed explanations. This problem covers integral calculus, partial fraction decomposition, and the use of logarithmic functions in integration. Suitable for college-level students and anyone studying integral calculus.

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