Math Problem Statement

integral e^-t

Solution

To compute the integral of ete^{-t}, we solve:

etdt\int e^{-t} \, dt

Solution:

The integral of ete^{-t} is computed as: etdt=et+C\int e^{-t} \, dt = -e^{-t} + C where CC is the constant of integration.


Would you like more details or have any questions?

Here are 5 related questions for exploration:

  1. How do you find the integral of eate^{-at}, where aa is a constant?
  2. What is the definite integral of ete^{-t} from 0 to infinity?
  3. How is ete^{-t} used in real-world applications like radioactive decay or population models?
  4. How would you compute the integral of tette^{-t}?
  5. What happens when you differentiate et-e^{-t}?

Tip: Always include the constant of integration CC when computing indefinite integrals!

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Math Problem Analysis

Mathematical Concepts

Calculus
Indefinite Integrals
Exponential Functions

Formulas

∫ e^(-t) dt = -e^(-t) + C

Theorems

Basic Exponential Integration

Suitable Grade Level

Grades 11-12