Math Problem Statement

Integrated cos inverse x root over tangent x into long tangent x into dx.

Solution

To solve the integral cos1(x)tan(x)ln(tan(x))dx\int \cos^{-1}(x) \sqrt{\tan(x)} \ln(\tan(x)) \, dx, let's delve into the steps methodically. Here's the solution approach:

Given:

cos1(x)tan(x)ln(tan(x))dx\int \cos^{-1}(x) \sqrt{\tan(x)} \ln(\tan(x)) \, dx

Let us simplify the process:

This integral is non-standard and highly complex, involving combinations of inverse trigonometric functions, roots, logarithms, and compositions of functions. Its evaluation likely requires advanced substitution techniques or numerical computation.

Key Techniques to Consider:

  1. Substitution: Let u=cos1(x)u = \cos^{-1}(x), then x=cos(u)x = \cos(u), and dx=sin(u)dudx = -\sin(u) du.
  2. Simplify the integral in terms of uu, transforming all terms (tan(x),ln(tan(x))\sqrt{\tan(x)}, \ln(\tan(x))) into expressions involving uu.

Substitutions (sketch):

  • tan(x)=sin(x)cos(x)\tan(x) = \frac{\sin(x)}{\cos(x)} and then write terms of uu.
  • The transformed integral may need approximation or numerical methods to compute due to its complexity.

Would you like me to break this down further or apply numerical computation for approximate evaluation?

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Math Problem Analysis

Mathematical Concepts

Integral Calculus
Inverse Trigonometric Functions
Logarithmic Functions
Trigonometric Identities

Formulas

Substitution: u = cos^(-1)(x), x = cos(u), dx = -sin(u) du
Trigonometric identity: tan(x) = sin(x)/cos(x)

Theorems

Fundamental Theorem of Calculus
Properties of Logarithmic and Trigonometric Functions

Suitable Grade Level

Undergraduate Mathematics or Advanced High School Calculus