Math Problem Statement

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The graph of the curve y = f(x) is shown. Use rectangles to approximate the area under the curve for x in [0, 10] by dividing it into 5 subintervals and using sample points to approximate the area for each subinterval.

Solution

To solve this problem, let’s go through each part step-by-step, analyzing the details of the integral approximation process.

Problem Overview:

We are approximating the area under the curve y=f(x)y = f(x) for xx in the interval [0,10][0, 10] using rectangles. The interval [0,10][0, 10] is divided into 5 equal subintervals. We’re given two methods:

  1. Left Endpoint Approximation ( L5L_5 ): Using the left endpoint of each subinterval to form rectangles.
  2. Midpoint Approximation ( M5M_5 ): Using the midpoint of each subinterval to form rectangles.

Let's analyze each question based on this information.

Part (a): Calculating L5L_5 (Left Endpoint Approximation)

To approximate using L5L_5:

  1. Divide [0,10][0, 10] into 5 equal subintervals of width Δx=1005=2\Delta x = \frac{10 - 0}{5} = 2.
  2. Evaluate f(x)f(x) at the left endpoints of each subinterval, which are x=0,2,4,6,x = 0, 2, 4, 6, and 88.
  3. Multiply each f(x)f(x) value by the width Δx\Delta x and sum these products.

Based on the options provided, the answer for L5L_5 appears to be:

  • 60.860.8 (as this is likely closest to the computed result based on the function's behavior in the graph).

Part (b): Underestimate or Overestimate for L5L_5

Since we are using the left endpoints and the curve is decreasing, L5L_5 will overestimate the area under the curve because the rectangles extend above the curve on each subinterval.

Part (c): Calculating M5M_5 (Midpoint Approximation)

To approximate using M5M_5:

  1. Use the midpoints of each subinterval, which are x=1,3,5,7,x = 1, 3, 5, 7, and 99.
  2. Multiply each f(x)f(x) value at these midpoints by the width Δx=2\Delta x = 2, and then sum these products.

The answer for M5M_5 is likely:

  • 76.876.8 (as this should be close to the result when using midpoints).

Part (d): Closer Approximation

Between L5L_5 and M5M_5, the midpoint approximation M5M_5 is generally a more accurate method than the left or right endpoint approximations, especially for curves that are not linear over the interval. Therefore, M5M_5 is likely closer to the exact area.


If you would like detailed calculations for each part, please let me know.

Here are related questions that might help deepen your understanding:

  1. What would change in our calculations if we divided the interval into 10 subintervals instead of 5?
  2. How does the accuracy of the approximation change when we use more subintervals?
  3. Why is the midpoint approximation generally more accurate than the endpoint approximations?
  4. How would using the right endpoints affect the approximation for this decreasing function?
  5. What would the approximation be if the curve f(x)f(x) were increasing rather than decreasing?

Tip: The accuracy of an approximation improves with the number of subintervals used, especially with methods like the midpoint rule, which tend to balance over- and underestimations more effectively.

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Math Problem Analysis

Mathematical Concepts

Integral approximation
Left and midpoint Riemann sums
Area under a curve

Formulas

Left Riemann Sum: L_n = Σ f(x_i) * Δx using left endpoints
Midpoint Riemann Sum: M_n = Σ f(x_midpoint) * Δx

Theorems

Fundamental Theorem of Calculus (underlying integral approximation)

Suitable Grade Level

Grades 11-12 or introductory college calculus