$$ \int20t^2\sqrt[3]{t}\differentialD t $$

We are tasked with solving the integral:

\[
\int 20t^2 \sqrt[3]{t} \, dt
\]

### Step 1: Rewrite the integrand
First, express $\sqrt[3]{t}$ as a fractional exponent. We have:

\[
\sqrt[3]{t} = t^{1/3}
\]

Thus, the integrand becomes:

\[
\int 20t^2 t^{1/3} \, dt
\]

### Step 2: Simplify the powers of $t$
Using the property of exponents, $t^a t^b = t^{a+b}$, we combine the powers of $t$:

\[
t^2 \cdot t^{1/3} = t^{2 + 1/3} = t^{7/3}
\]

Thus, the integral is now:

\[
\int 20 t^{7/3} \, dt
\]

### Step 3: Apply the power rule of integration
The power rule states that:

\[
\int t^n \, dt = \frac{t^{n+1}}{n+1} + C
\]

Here, $n = \frac{7}{3}$, so we apply the power rule:

\[
\int 20 t^{7/3} \, dt = 20 \cdot \frac{t^{7/3 + 1}}{7/3 + 1} + C
\]

### Step 4: Simplify the exponent and the denominator
We simplify $7/3 + 1$:

\[
7/3 + 1 = 7/3 + 3/3 = 10/3
\]

Thus, the integral becomes:

\[
20 \cdot \frac{t^{10/3}}{10/3} + C
\]

### Step 5: Simplify the fraction
Dividing by $10/3$ is equivalent to multiplying by $3/10$:

\[
20 \cdot \frac{3}{10} \cdot t^{10/3} = 6 t^{10/3}
\]

### Final Answer:
\[
\int 20 t^2 \sqrt[3]{t} \, dt = 6 t^{10/3} + C
\]

Would you like further details or explanations on any step?

### Related Questions:
1. How do you integrate other fractional powers of $t$?
2. What is the general power rule for integration?
3. How do you handle integrals with radicals and exponents?
4. Can integration by substitution be applied here?
5. How does this integral relate to definite integrals?

### Tip:
Always simplify the integrand as much as possible before applying integration rules, especially by combining like terms or converting roots to fractional exponents.

This solution explains how to solve the integral of 20t^2 multiplied by the cube root of t using the power rule for integration. It includes key steps like simplifying exponents, applying the power rule, and combining like terms. Suitable for students studying undergraduate or advanced high school calculus.

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