Math Problem Statement

Let X and Y be independent random variables such that Var X = 5 and Var[Y] = 9. (a) [4 pts] Prove that 2X and 3Y are independent. (b) [6 pts] What is the standard deviation of 2X + 3Y?

Solution

Part (a): Proving 2X2X and 3Y3Y are Independent

To prove that 2X2X and 3Y3Y are independent, we use the fact that XX and YY are independent random variables. Given that 2X2X is just a linear transformation of XX and 3Y3Y is a linear transformation of YY, these two linear transformations will also be independent.

Reasoning:

Two random variables AA and BB are independent if and only if the joint distribution of AA and BB can be factored into the product of their marginal distributions, i.e.,

P(Aa,Bb)=P(Aa)P(Bb)for all a,b.P(A \leq a, B \leq b) = P(A \leq a) \cdot P(B \leq b) \quad \text{for all } a, b.

Since 2X2X and 3Y3Y are obtained by multiplying independent random variables XX and YY by constants, we know that for independent random variables XX and YY:

P(2Xa,3Yb)=P(Xa2)P(Yb3),P(2X \leq a, 3Y \leq b) = P\left(X \leq \frac{a}{2}\right) \cdot P\left(Y \leq \frac{b}{3}\right),

which is equivalent to the product of the marginal distributions of 2X2X and 3Y3Y. Therefore, 2X2X and 3Y3Y are independent.

Part (b): Standard Deviation of 2X+3Y2X + 3Y

We are given:

Var(X)=5,Var(Y)=9.\text{Var}(X) = 5, \quad \text{Var}(Y) = 9.

We need to find the standard deviation of 2X+3Y2X + 3Y.

Step 1: Calculate the Variance of 2X+3Y2X + 3Y

Since XX and YY are independent, the variance of a linear combination of independent variables is given by:

Var(2X+3Y)=Var(2X)+Var(3Y).\text{Var}(2X + 3Y) = \text{Var}(2X) + \text{Var}(3Y).

Now, using the property that if aa is a constant, Var(aX)=a2Var(X)\text{Var}(aX) = a^2 \cdot \text{Var}(X), we have:

Var(2X)=22Var(X)=45=20,\text{Var}(2X) = 2^2 \cdot \text{Var}(X) = 4 \cdot 5 = 20,

Var(3Y)=32Var(Y)=99=81.\text{Var}(3Y) = 3^2 \cdot \text{Var}(Y) = 9 \cdot 9 = 81.

Thus,

Var(2X+3Y)=20+81=101.\text{Var}(2X + 3Y) = 20 + 81 = 101.

Step 2: Calculate the Standard Deviation of 2X+3Y2X + 3Y

The standard deviation is the square root of the variance:

SD(2X+3Y)=Var(2X+3Y)=101.\text{SD}(2X + 3Y) = \sqrt{\text{Var}(2X + 3Y)} = \sqrt{101}.

Final Answer:

  • Part (a): 2X2X and 3Y3Y are independent because they are linear transformations of independent variables XX and YY.
  • Part (b): The standard deviation of 2X+3Y2X + 3Y is 101\sqrt{101}.

Do you have any questions or would you like more details on any of the steps?

Related Questions:

  1. What does it mean for two random variables to be independent?
  2. How does a linear transformation affect the independence of random variables?
  3. What is the relationship between variance and standard deviation?
  4. Can you provide an example where two variables are not independent, and how their variance would be calculated differently?
  5. What are the properties of variance when dealing with linear combinations of random variables?

Tip:

When dealing with the variance of a sum of independent random variables, always remember that the covariance term vanishes (since covariance between independent variables is zero), simplifying the calculation to the sum of individual variances.

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Math Problem Analysis

Mathematical Concepts

Probability Theory
Variance
Standard Deviation
Independence of Random Variables
Linear Transformations

Formulas

Var(aX) = a^2 * Var(X)
Var(X + Y) = Var(X) + Var(Y) for independent X and Y
Standard Deviation = sqrt(Variance)

Theorems

Independence of linear transformations of independent random variables
Properties of variance for linear combinations of independent variables

Suitable Grade Level

Undergraduate