Math Problem Statement

Given f(x) = x - 2sin(x), 0 ≤ x ≤ 3π, find the interval on which f is increasing or decreasing and find the local maximum and minimum values of f.

Solution

It appears you have uploaded a photograph with several math problems. Let's address each question one by one, starting with problem number 23 related to the function f(x)=x2sinxf(x) = x - 2\sin x over the interval 0x3π0 \leq x \leq 3\pi.

Part (a): Find the interval on which ff is increasing or decreasing.

To determine where the function is increasing or decreasing, we first need to find its derivative and analyze the sign of the derivative:

f(x)=12cosxf'(x) = 1 - 2\cos x

We'll find the values of xx for which f(x)=0f'(x) = 0 to identify critical points:

12cosx=01 - 2\cos x = 0 cosx=12\cos x = \frac{1}{2}

The cosine function equals 12\frac{1}{2} at specific standard angles within the given interval 0x3π0 \leq x \leq 3\pi:

x=π3,5π3,7π3,11π3x = \frac{\pi}{3}, \frac{5\pi}{3}, \frac{7\pi}{3}, \frac{11\pi}{3}

Next, we analyze the sign of f(x)f'(x) in the intervals defined by these critical points to determine where the function is increasing (where f(x)>0f'(x) > 0) and decreasing (where f(x)<0f'(x) < 0).

Part (b): Find the local maximum and minimum values of ff.

The local maxima and minima occur at these critical points where the derivative changes sign. We can calculate f(x)f(x) at these points and check the sign changes in f(x)f'(x) around them to identify maxima and minima.

I'll now perform these calculations to complete both parts (a) and (b) of problem 23.

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivatives
Increasing and Decreasing Functions
Maxima and Minima

Formulas

f'(x) = 1 - 2cos(x)
Critical points where f'(x) = 0
Cosine values: cos(θ) = 1/2 at θ = π/3, 5π/3, etc.

Theorems

Derivative Test for Increasing/Decreasing Intervals
First Derivative Test for Maxima and Minima

Suitable Grade Level

Grade 12 or College-Level Calculus