Math Problem Statement

There are a total of 117 foreign language students in a high school where they offer Spanish, French and German. There are 29 students that take at least 2 languages at once. If there are 50 Spanish students, 42 French students and 50 German students, how many students take all three languages at once?

Solution

Let's define the sets:

  • Let SS be the set of students who take Spanish.
  • Let FF be the set of students who take French.
  • Let GG be the set of students who take German.

The given information is:

  • S=50|S| = 50 (students who take Spanish),
  • F=42|F| = 42 (students who take French),
  • G=50|G| = 50 (students who take German),
  • SFG=117|S \cup F \cup G| = 117 (total number of foreign language students),
  • 29 students take at least 2 languages.

We are tasked with finding the number of students who take all three languages, which we'll denote as xx.

Step 1: Apply the Principle of Inclusion-Exclusion

The principle of inclusion-exclusion for three sets is given by the formula:

SFG=S+F+GSFFGGS+SFG|S \cup F \cup G| = |S| + |F| + |G| - |S \cap F| - |F \cap G| - |G \cap S| + |S \cap F \cap G|

Here:

  • SFG=x|S \cap F \cap G| = x is the number of students taking all three languages.
  • The sum of students taking at least 2 languages is given as 29.

We need to express the total number of students taking exactly two languages in terms of xx. Define:

  • SF|S \cap F| as the number of students taking both Spanish and French,
  • FG|F \cap G| as the number of students taking both French and German,
  • GS|G \cap S| as the number of students taking both German and Spanish.

Let a=SFxa = |S \cap F| - x, b=FGxb = |F \cap G| - x, and c=GSxc = |G \cap S| - x, where a+b+c+3x=29a + b + c + 3x = 29. The

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Math Problem Analysis

Mathematical Concepts

Set Theory
Principle of Inclusion-Exclusion

Formulas

|S ∪ F ∪ G| = |S| + |F| + |G| - |S ∩ F| - |F ∩ G| - |G ∩ S| + |S ∩ F ∩ G|

Theorems

Inclusion-Exclusion Principle

Suitable Grade Level

Grades 10-12