Math Problem Statement
find the integral of 1/x^2 between[-1,1]
Solution
The integral of over the interval is improper because the integrand becomes undefined at . We need to split the integral into two parts and check whether each part converges:
1. Integral :
The antiderivative of is:
2. Applying limits:
For the interval , splitting the integral around the singularity at , we write:
Evaluating each part:
-
For :
-
For :
Adding the results:
As , the term , so the integral diverges.
Conclusion:
The integral does not converge because the function has a singularity at , causing the integral to diverge to infinity.
Would you like further clarification or visualizations for this?
- What is an improper integral?
- How can we evaluate improper integrals with infinite limits?
- What conditions cause an integral to diverge?
- Can an integral diverge on only part of its domain?
- What are other examples of integrals with singularities?
Tip: Always check for singularities in the integrand or limits of integration to determine if an integral is improper.
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Math Problem Analysis
Mathematical Concepts
Calculus
Improper Integrals
Definite Integrals
Singularities
Formulas
Integral of 1/x^2: ∫(1/x^2) dx = -1/x
Improper Integral Splitting: ∫(a to b) f(x) dx = ∫(a to c) f(x) dx + ∫(c to b) f(x) dx, where c is the singularity point
Theorems
Divergence of Improper Integrals
Suitable Grade Level
College Calculus or Advanced High School AP Calculus
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