Math Problem Statement

Why might we need to use implicit differentiation? Choose all that apply for \( \frac{d}{dx}(y^2) = \frac{d}{dx}(f(x))^2 \).

Solution

For these questions:

Question 1

The best answer for why we might need to use implicit differentiation is:

  • The equation giving the relationship between the variable is NOT solved for the dependent variable.

Explanation: Implicit differentiation is often used when we have an equation that defines a relationship between variables, but it’s difficult or impossible to explicitly solve for one variable in terms of the other. By differentiating both sides of the equation with respect to the independent variable, we can find the derivative even without an explicit function.

Question 2

To differentiate y2=(f(x))2y^2 = (f(x))^2 with respect to xx, we apply the chain rule.

  1. For ddx(y2)\frac{d}{dx}(y^2): ddx(y2)=2ydydx=2yf(x)(since y=f(x))\frac{d}{dx}(y^2) = 2y \cdot \frac{dy}{dx} = 2y \cdot f'(x) \quad \text{(since } y = f(x) \text{)}

  2. This means the correct answers are:

    • 2ydydx2y \cdot \frac{dy}{dx}
    • 2f(x)f(x)2f(x) \cdot f'(x)

Thus, the selected answers are:

  • 2y(dy/dx)*
  • 2f(x)f'(x)

Would you like a deeper explanation of the chain rule application or any of these concepts?

Follow-up Questions

  1. How is implicit differentiation used in related rates problems?
  2. What are the typical scenarios where explicit differentiation is preferred over implicit?
  3. How would the process change if yy were expressed explicitly in terms of xx?
  4. How does the chain rule apply in the differentiation of composite functions?
  5. Why is ddx(y2)\frac{d}{dx}(y^2) not simply 2y2y?

Tip

Remember, when differentiating an expression involving a function of xx, always apply the chain rule if that function is itself not isolated or has multiple terms squared.

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Math Problem Analysis

Mathematical Concepts

Implicit Differentiation
Chain Rule
Differentiation of Composite Functions

Formulas

\( \frac{d}{dx}(y^2) = 2y \cdot \frac{dy}{dx} \)
\( \frac{d}{dx}(f(x))^2 = 2f(x) \cdot f'(x) \)

Theorems

Chain Rule

Suitable Grade Level

Grades 11-12 or College Level Calculus