Math Problem Statement

Point P'(-6, -4) is the image of point P(-2, 3) under a translation. What is the image of (5, -1) under the same translation?

Solution

To solve this problem, we first need to determine the translation vector that moves point P(2,3)P(-2, 3) to point P(6,4)P'(-6, -4).

  1. Calculate the translation vector: Translation vector=(x,y)(x,y)=(6(2),43)=(6+2,43)=(4,7)\text{Translation vector} = (x', y') - (x, y) = (-6 - (-2), -4 - 3) = (-6 + 2, -4 - 3) = (-4, -7)

    So, the translation vector is (4,7)(-4, -7).

  2. Apply the translation to the point (5,1)(5, -1): (5,1)+(4,7)=(54,17)=(1,8)(5, -1) + (-4, -7) = (5 - 4, -1 - 7) = (1, -8)

  3. Conclusion: The image of the point (5,1)(5, -1) under the same translation is (1,8)(1, -8).

Answer: B. (1,8)(1, -8)

Would you like a detailed breakdown of each step or have any other questions?

Related Questions

  1. How do you determine the translation vector between two points?
  2. Can you explain translations in the context of geometric transformations?
  3. What is the general formula for translating a point by a vector?
  4. How would you find the original point if you know the translated image and the translation vector?
  5. What other transformations can be applied to points on a coordinate plane?

Tip

When translating points, always remember to apply the vector's components to the respective xx and yy coordinates to obtain the translated point.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Translations in Geometry

Formulas

Translation vector formula: (x', y') - (x, y)

Theorems

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Suitable Grade Level

Grades 7-9