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The graph provided shows the function \( f(x) \), and you're asked to determine the points where the function is **not differentiable**. 

In general, a function is not differentiable at points where:
1. There is a **sharp corner** or **cusp**.
2. There is a **discontinuity**.
3. The **tangent** becomes **vertical**.

### Analysis of the graph:
- **At \( x = 0 \)**: The graph has a smooth curve and appears continuous, meaning it is differentiable at this point. This explains why \( x = 0 \) is marked as differentiable (green checkmark).
- **At \( x = -2 \)**: There seems to be a sharp corner, meaning the slope from the left and right are different. This is where the function is **not differentiable**.
- **At \( x = 2 \)**: There is a cusp (sharp turning point), so the function is not differentiable here either.

Thus, the smaller value where \( f(x) \) is not differentiable is \( x = -2 \).

### Final answer:
- \( x = -2 \) (smaller value).
- \( x = 2 \) (already provided as the larger value is \( x = 0 \)).

Let me know if you would like further details or have any questions!

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Here are five related questions to expand your understanding:
1. What is the formal definition of differentiability at a point?
2. How do you determine the slope from a graph to identify a sharp corner?
3. Can a function be continuous but not differentiable?
4. What is the difference between a cusp and a vertical tangent in terms of differentiability?
5. How does the concept of limits relate to differentiability?

**Tip**: A smooth curve means the function is differentiable, while sharp changes in direction or breaks indicate non-differentiability.

The graph of f is given. State the numbers at which f is not differentiable.

Learn how to identify points where the function f(x) is not differentiable from its graph. This problem covers key calculus concepts, including sharp corners, cusps, and discontinuities, and is suitable for students in Grades 10-12.

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