The equation provided in your query appears to describe a linear equation where the slope and the y-intercept are given as follows:

1. Slope = 1
2. Y-intercept = 1.5

In slope-intercept form, $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept, the equation for this line would be:

$y = 1x + 1.5 \quad \text{or simply} \quad y = x + 1.5$

This tells us:

• The line rises one unit vertically for every one unit it moves horizontally (slope $m = 1$).
• The line crosses the y-axis at $y = 1.5$.

Let me know if you’d like further clarification or assistance analyzing this graph.

Here are 5 related questions for practice:

1. How do you find the slope of a line from two points on the graph?
2. What is the slope and y-intercept of the equation $y = 2x - 3$?
3. How do you convert a linear equation from standard form to slope-intercept form?
4. What does a slope of 0 represent on a graph?
5. How does the slope affect the steepness of a line?

Tip: To confirm a slope visually, choose two points on the line, calculate the rise over run ($\frac{\Delta y}{\Delta x}$), and verify it matches the equation.