Math Problem Statement

From previous studies, it is concluded that 49% of workers indicate that they are satisfied with their job. A researcher claims it has increased and decides to survey 100 adults. Test the researcher's claim at the α = 0.05 significance level.

Solution

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Problem Summary:

The task involves hypothesis testing about workers' job satisfaction. It tests whether the proportion of satisfied workers (based on new sample data) is higher than 49% (the established value from prior studies). The significance level is α=0.05\alpha = 0.05.

Steps and Explanation:

Part a: Verify np^(1p^)10n \hat{p}(1 - \hat{p}) \geq 10

  • n=100n = 100 (sample size), and p^=0.49\hat{p} = 0.49 (hypothesized proportion).
  • Calculation: np^(1p^)=100×0.49×(10.49)=25.0n \hat{p}(1 - \hat{p}) = 100 \times 0.49 \times (1 - 0.49) = 25.0 Since 25.01025.0 \geq 10, the condition is satisfied.

Part b: Hypotheses in Symbolic Form

  • Null hypothesis (H0H_0): The proportion of satisfied workers has not increased. H0:p=0.49H_0: p = 0.49.
  • Alternative hypothesis (HaH_a): The proportion of satisfied workers has increased. Ha:p>0.49H_a: p > 0.49.

Part c: Compute the Test Statistic (zz)

  • Sample statistic: 37 satisfied workers out of 100 (p^=0.37\hat{p} = 0.37).
  • Formula for zz: z=p^pp(1p)nz = \frac{\hat{p} - p}{\sqrt{\frac{p(1-p)}{n}}} Substituting: z=0.370.490.49×0.51100=0.120.002499=0.120.049992.40z = \frac{0.37 - 0.49}{\sqrt{\frac{0.49 \times 0.51}{100}}} = \frac{-0.12}{\sqrt{0.002499}} = \frac{-0.12}{0.04999} \approx -2.40

Part d: Compute the pp-Value

  • The test is one-tailed (since Ha:p>0.49H_a: p > 0.49).
  • From the zz-table: p=P(Z<2.40)0.0082p = P(Z < -2.40) \approx 0.0082

Part e: Decision Based on α=0.05\alpha = 0.05

  • Compare pp-value (0.0082)(0.0082) with α(0.05)\alpha (0.05): p<αp < \alpha Therefore, reject the null hypothesis.

Part f: Conclusion

  • There is sufficient evidence to support the claim that the proportion of workers satisfied with their job has increased.

Questions for Further Analysis:

  1. Why is it important to verify np^(1p^)10n \hat{p}(1 - \hat{p}) \geq 10 before conducting the test?
  2. How does the significance level (α\alpha) impact the decision-making process in hypothesis testing?
  3. What are the potential implications if a Type I error is made in this case?
  4. Can the conclusions of this test be generalized to the entire population? Why or why not?
  5. How would the test change if we were conducting a two-tailed test instead of a one-tailed test?

Tip:

Always ensure the assumptions for hypothesis testing (e.g., sample size, independence, normality) are checked before proceeding with calculations to maintain the validity of your results.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Proportions
Significance Testing
z-test

Formulas

n * p̂ * (1 - p̂) >= 10
z = (p̂ - p) / sqrt(p * (1 - p) / n)

Theorems

Central Limit Theorem

Suitable Grade Level

Grades 11-12, College Introductory Statistics