Math Problem Statement

The manufacturer of a particular brand of tires claims they average at least 79,000 km before needing to be replaced. From past studies of this tire, it is known that the population standard deviation is 12,800 km.

A survey of tire owners was conducted to determine if the mileage of the tires is lower than 79,000 km. From the 32 tires sampled, the mean lifespan was 76,500 km. Testing at αα = 2%, can we prove that the data is inconsistent with the manufacturers claim?

We should use a ? z t  test.

What are the correct hypotheses?  H0H0: Select an answer μ σ² s s² x̄ p̂ p σ  ? > ≠ ≤ ≥ < =   H1H1: Select an answer p̂ s s² μ σ x̂ p σ²  ? > = ≤ ≠ < ≥  

Based on the hypotheses, find the following (round correct to at least 2 decimal places):

Test Statistic = 

Critical Value =  (note the direction of H1H1)

The correct decision is to Select an answer Accept the alternative hypotheis Accept the null hypothesis Reject the null hypothesis Fail to reject the null hypothesis  .

The correct conclusion would be: There is not enough evidence to conclude that the tires do not last less than the kilometres claimed

There is not enough evidence to conclude that the tires last less than the kilometres claimed

There is enough evidence to conclude that the tires do not last less than the kilometres claimed

There is enough evidence to conclude that the tires last less than the kilometres claimed

Solution

This problem involves hypothesis testing to determine if the tire lifespan is lower than the manufacturer’s claim of 79,000 km. Let us solve step by step.


1. Determine the appropriate test: z-test or t-test?

Since the population standard deviation (σ=12,800\sigma = 12,800) is known and the sample size is 32 (n>30n > 30), we use a z-test.


2. State the hypotheses

  • H0H_0: The mean lifespan of the tires is greater than or equal to 79,000 km (μ79,000\mu \geq 79,000).
  • H1H_1: The mean lifespan of the tires is less than 79,000 km (μ<79,000\mu < 79,000).

Mathematically: H0:μ79,000andH1:μ<79,000H_0: \mu \geq 79,000 \quad \text{and} \quad H_1: \mu < 79,000

This is a one-tailed test (left-tailed) because we are testing if the mileage is lower.


3. Test statistic formula

For a z-test, the test statistic is: z=xˉμσ/nz = \frac{\bar{x} - \mu}{\sigma / \sqrt{n}}

Where:

  • xˉ=76,500\bar{x} = 76,500 km (sample mean),
  • μ=79,000\mu = 79,000 km (claimed mean),
  • σ=12,800\sigma = 12,800 km (population standard deviation),
  • n=32n = 32 (sample size).

Substitute the values: z=76,50079,00012,800/32=2,50012,800/5.6569=2,5002,263.131.10z = \frac{76,500 - 79,000}{12,800 / \sqrt{32}} = \frac{-2,500}{12,800 / 5.6569} = \frac{-2,500}{2,263.13} \approx -1.10

4. Critical value

At a significance level of α=0.02\alpha = 0.02 for a one-tailed (left-tailed) test, the critical z-value is: zcritical=2.05(from z-tables or statistical software).z_{\text{critical}} = -2.05 \quad \text{(from z-tables or statistical software)}.


5. Decision rule

  • If zzcriticalz \leq z_{\text{critical}}, reject H0H_0.
  • If z>zcriticalz > z_{\text{critical}}, fail to reject H0H_0.

Here: z=1.10andzcritical=2.05.z = -1.10 \quad \text{and} \quad z_{\text{critical}} = -2.05. Since 1.10>2.05-1.10 > -2.05, we fail to reject H0H_0.


6. Conclusion

The correct decision is:

  • Fail to reject the null hypothesis.

The correct conclusion is:

  • There is not enough evidence to conclude that the tires last less than the kilometers claimed.

Summary of Results

  1. Test Type: z-test
  2. Hypotheses:
    H0:μ79,000H1:μ<79,000H_0: \mu \geq 79,000 \quad H_1: \mu < 79,000
  3. Test Statistic: z=1.10z = -1.10
  4. Critical Value: zcritical=2.05z_{\text{critical}} = -2.05
  5. Decision: Fail to reject H0H_0.
  6. Conclusion: There is not enough evidence to conclude that the tires last less than the kilometers claimed.

Would you like to explore related concepts or clarify any steps?
Here are 5 related questions for practice:

  1. What changes in the conclusion if the sample mean was 75,000 km instead of 76,500 km?
  2. How does increasing the sample size impact the test statistic?
  3. What would the decision be if α=5%\alpha = 5\% instead of 2%2\%?
  4. What is the relationship between the significance level and the probability of a Type I error?
  5. How would a two-tailed test differ in hypothesis and critical values?

Tip: When conducting hypothesis tests, always sketch a bell curve to visualize the critical regions and test statistic placement.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Normal Distribution
z-Test

Formulas

z = (x̄ - μ) / (σ / √n)

Theorems

Central Limit Theorem

Suitable Grade Level

Grades 10-12, College Introductory Statistics