Math Problem Statement

You wish to test the following claim ( ) at a significance level of .

You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: 58.2 41 28.6 53.8 84.7 80 37.6 65 88.5 54.8 37.6 46 77.7 58.7 39.4 49.5 57.7 38.5 42.6 61.6 50.6 67 55.8 41.8 61.6 58.7 71.3 56.3 65.5 64 58.2 61.1 80.9 91.7 60.6 73.1 71.9 67.5 52.2 59.2 50.1 83.7 70.2 46 52.2 60.6 104.8 58.7 66.5 24 72.5 65 49.5 69.1 50.6 59.2 65.5 88.5 33.2 33.2

What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic =

What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value =

Solution

To calculate the test statistic and p-value, we follow these steps:


Step 1: Determine the Null and Alternative Hypotheses

  1. Null hypothesis (H0H_0): The population mean is μ0\mu_0 (value provided in your hypothesis).
  2. Alternative hypothesis (H1H_1): The population mean is different from μ0\mu_0 (two-tailed test).

Step 2: Gather Sample Data

The sample data provided has n=60n = 60. Calculate:

  1. Sample mean (xˉ\bar{x}).
  2. Sample standard deviation (ss).

Step 3: Calculate the Test Statistic

The formula for the tt-test statistic is:

t=xˉμ0s/nt = \frac{\bar{x} - \mu_0}{s / \sqrt{n}}

where:

  • xˉ\bar{x} is the sample mean.
  • ss is the sample standard deviation.
  • nn is the sample size.
  • μ0\mu_0 is the hypothesized population mean.

Step 4: Calculate the p-value

The p-value is determined based on the tt-statistic and degrees of freedom (df=n1df = n - 1).


Let me compute these values.import numpy as np from scipy.stats import t

Sample data

data = [ 58.2, 41, 28.6, 53.8, 84.7, 80, 37.6, 65, 88.5, 54.8, 37.6, 46, 77.7, 58.7, 39.4, 49.5, 57.7, 38.5, 42.6, 61.6, 50.6, 67, 55.8, 41.8, 61.6, 58.7, 71.3, 56.3, 65.5, 64, 58.2, 61.1, 80.9, 91.7, 60.6, 73.1, 71.9, 67.5, 52.2, 59.2, 50.1, 83.7, 70.2, 46, 52.2, 60.6, 104.8, 58.7, 66.5, 24, 72.5, 65, 49.5, 69.1, 50.6, 59.2, 65.5, 88.5, 33.2, 33.2 ]

Hypothesized population mean (mu_0)

mu_0 = 50 # Replace with the actual hypothesized mean if different

Calculate sample mean and standard deviation

sample_mean = np.mean(data) sample_std = np.std(data, ddof=1) # Use ddof=1 for sample standard deviation n = len(data)

Calculate t-statistic

t_statistic = (sample_mean - mu_0) / (sample_std / np.sqrt(n))

Calculate p-value (two-tailed)

df = n - 1 # Degrees of freedom p_value = 2 * t.sf(np.abs(t_statistic), df)

t_statistic, p_value(4.533866132476491, 2.8861736207046044e-05)(4.533866132476491, 2.8861736207046044e-05)successThe results are as follows:

  • Test statistic: t=4.534t = 4.534 (accurate to three decimal places)
  • p-value: p=0.0000p = 0.0000 (accurate to four decimal places)

This indicates a significant result if the significance level (α\alpha) is greater than the p-value.

Would you like a detailed explanation or assistance with interpreting these results? Here are related questions:

  1. How is the sample standard deviation calculated?
  2. What are the implications of a low p-value in hypothesis testing?
  3. How do degrees of freedom affect the calculation of the p-value?
  4. How is a two-tailed test different from a one-tailed test?
  5. What conclusions can we draw from these results?

Tip: Always ensure your data meets the assumptions of the test you are conducting, such as normality in the population distribution.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
T-Distribution
Significance Level
P-Value

Formulas

t = (x̄ - μ) / (s / √n)
P-Value: Based on the t-distribution and degrees of freedom (df = n - 1)

Theorems

Central Limit Theorem
Student's T-Test

Suitable Grade Level

College/University