Math Problem Statement

A random sample of 78 eighth grade​ students' scores on a national mathematics assessment test has a mean score of 278. This test result prompts a state school administrator to declare that the mean score for the​ state's eighth graders on this exam is more than 270. Assume that the population standard deviation is 40. At alphaequals0.11​, is there enough evidence to support the​ administrator's claim? Complete parts​ (a) through​ (e). ​(c) Find the​ P-value.

Solution

To solve this hypothesis test and find the P-value, we need to follow these steps:

Given:

  • Sample size (nn) = 78
  • Sample mean (xˉ\bar{x}) = 278
  • Population standard deviation (σ\sigma) = 40
  • Hypothesized population mean (μ0\mu_0) = 270
  • Significance level (α\alpha) = 0.11

Step 1: Set up the hypotheses.

  • Null hypothesis (H0H_0): μ=270\mu = 270 (The mean score is 270)
  • Alternative hypothesis (HaH_a): μ>270\mu > 270 (The mean score is greater than 270)

Step 2: Calculate the test statistic.

We use the Z-test for the population mean because the population standard deviation is known. The formula for the Z-test statistic is:

Z=xˉμ0σnZ = \frac{\bar{x} - \mu_0}{\frac{\sigma}{\sqrt{n}}}

Where:

  • xˉ\bar{x} is the sample mean,
  • μ0\mu_0 is the hypothesized population mean,
  • σ\sigma is the population standard deviation,
  • nn is the sample size.

Substitute the given values into the formula:

Z=2782704078Z = \frac{278 - 270}{\frac{40}{\sqrt{78}}}

First, calculate the denominator:

4078=408.834.53\frac{40}{\sqrt{78}} = \frac{40}{8.83} \approx 4.53

Now, calculate the Z-score:

Z=2782704.5384.531.77Z = \frac{278 - 270}{4.53} \approx \frac{8}{4.53} \approx 1.77

Step 3: Find the P-value.

Since this is a one-tailed test (right-tailed), we can find the P-value by looking up the Z-value in the standard normal distribution table, or using a calculator. The Z-value of 1.77 corresponds to a P-value of approximately 0.0384.

Step 4: Conclusion.

Now that we have the P-value, we can compare it to the significance level α=0.11\alpha = 0.11.

  • If the P-value is less than α\alpha, we reject the null hypothesis.
  • If the P-value is greater than α\alpha, we fail to reject the null hypothesis.

In this case, the P-value (0.0384) is less than the significance level (α=0.11\alpha = 0.11). Therefore, we reject the null hypothesis.

Final Answer:

There is enough evidence to support the administrator's claim that the mean score for the state's eighth graders is greater than 270.


Would you like a more detailed explanation of any part of the process or further assistance with related concepts?

Here are some related questions for you to explore:

  1. How do you perform a Z-test for proportions?
  2. What is the difference between a one-tailed and a two-tailed test?
  3. How do you calculate the confidence interval for a population mean using the Z-distribution?
  4. What are the assumptions for using a Z-test?
  5. How does increasing the sample size affect the results of a hypothesis test?

Tip: Always ensure that your sample size is large enough (typically n>30n > 30) for the Z-test to be valid when the population standard deviation is known.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Z-Test
P-Value
Normal Distribution

Formulas

Z = (\bar{x} - \mu_0) / (\sigma / \sqrt{n})
Z-value for P-value lookup

Theorems

Central Limit Theorem
Z-Test for Population Mean

Suitable Grade Level

Grades 10-12