Math Problem Statement

Past studies have indicated that the percentage of smokers was estimated to be about 30%. Given the new smoking cessation programs that have been implemented, you now believe that the percentage of smokers has reduced. You randomly surveyed 2246 people and found that 619 smoke. Use a 0.05 significance level to test the claim that the percentage of smokers has reduced.

Solution

To solve this hypothesis test, let's go through each part of the problem step-by-step.

Given Information

  • The initial percentage of smokers was estimated to be about 30%30\%.
  • After new smoking cessation programs, you believe the percentage has reduced.
  • A sample of 2246 people was surveyed, and 619 of them smoke.
  • Significance level α=0.05\alpha = 0.05.

Problem Breakdown

(a) Identify the Null and Alternative Hypotheses

  1. Null Hypothesis ( H0H_0 ): The percentage of smokers has not reduced, i.e., it is still 30%30\%. H0:p=0.30H_0: p = 0.30

  2. Alternative Hypothesis ( H1H_1 ): The percentage of smokers has reduced. H1:p<0.30H_1: p < 0.30

(b) Type of Hypothesis Test

Since the claim is that the percentage of smokers has reduced, we are testing for a decrease. This calls for a left-tailed test.

(c) Significance Level

The significance level α\alpha is given as 0.05.

(d) Calculate the Test Statistic

  1. Sample Proportion ( p^\hat{p} ): p^=61922460.2756\hat{p} = \frac{619}{2246} \approx 0.2756

  2. Standard Error ( SESE ): SE=p0(1p0)n=0.30×(10.30)22460.0096SE = \sqrt{\frac{p_0 (1 - p_0)}{n}} = \sqrt{\frac{0.30 \times (1 - 0.30)}{2246}} \approx 0.0096

  3. Z-Test Statistic ( ZZ ): Z=p^p0SE=0.27560.300.00962.52Z = \frac{\hat{p} - p_0}{SE} = \frac{0.2756 - 0.30}{0.0096} \approx -2.52

(e) Calculate the p-Value

For a left-tailed test, we need to find the p-value corresponding to Z=2.52Z = -2.52. Using the Z-table, a Z-score of -2.52 gives a p-value of approximately 0.0059.

(f) Do You Reject the Null Hypothesis?

Since the p-value (0.0059) is less than the significance level α=0.05\alpha = 0.05, we reject the null hypothesis.

(g) Conclusion

Since we rejected the null hypothesis, we conclude:

There is sufficient evidence to warrant rejection of the claim that the percentage of smokers is less than 30%.


Summary of Answers

  1. (a) H0:p=0.30H_0: p = 0.30; H1:p<0.30H_1: p < 0.30
  2. (b) Left-tailed
  3. (c) Significance level: 0.05
  4. (d) Test statistic: Z2.52Z \approx -2.52
  5. (e) p-value: 0.0059
  6. (f) Reject the null hypothesis.
  7. (g) Conclusion: There is sufficient evidence to warrant rejection of the claim that the percentage of smokers is less than 30%.

Would you like more details on any specific part? Here are some further questions you might consider:

  1. How is the standard error in hypothesis testing calculated?
  2. Why do we use a left-tailed test in this scenario?
  3. What does rejecting the null hypothesis mean in practical terms?
  4. How do we interpret the p-value in the context of this test?
  5. What would happen if the significance level were lowered to 0.01?

Tip: Remember that a p-value less than the significance level indicates strong evidence against the null hypothesis.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Proportion Testing
Statistics

Formulas

Sample Proportion: \( \hat{p} = \frac{x}{n} \)
Standard Error for Proportion: \( SE = \sqrt{\frac{p_0 (1 - p_0)}{n}} \)
Z-test Statistic for Proportion: \( Z = \frac{\hat{p} - p_0}{SE} \)

Theorems

Central Limit Theorem (for proportion testing)

Suitable Grade Level

College Statistics or AP Statistics