Math Problem Statement

Some manufacturers claim that non-hybrid sedan cars have a lower mean miles-per-gallon (mpg) than hybrid ones. Suppose that consumers test 256 hybrid sedans and get a mean of 28 mpg with a standard deviation of 4.25 mpg. Also, 246 non-hybrid sedans get a mean of 27 mpg with a standard deviation of 6.5 mpg. Suppose that both populations are known to be normal distributed.

Conduct a hypothesis test to evaluate the manufacturers' claim. Test at a 7% level of significance.

Let population 1 denote non-hybrids and population 2 denote hybrids.

(a) H0 : μ1

μ2

(b) Ha : μ1

μ2

(c) In words, state what your random variable represents.

The random variable is the
miles per gallon of non-hybrid sedans and hybrid sedans.

(d) Select the distribution to use for the test.

Xˉ1−Xˉ2∼N[μ1−μ2,σ]

Xˉ1−Xˉ2∼N[μ,σ]

tdf

Xˉ∼N[μ,σ]

Xˉ1−Xˉ2∼N[σ,μ]

(e) What is the test statistic?

Round your answer to three decimal places

Solution

Let's go through each part of the problem step by step.

(a) Null Hypothesis (H0H_0):

The null hypothesis is that the mean miles-per-gallon (mpg) of non-hybrid sedans (μ1\mu_1) is greater than or equal to the mean mpg of hybrid sedans (μ2\mu_2).

H0:μ1μ2H_0: \mu_1 \geq \mu_2

(b) Alternative Hypothesis (HaH_a):

The alternative hypothesis is that the mean mpg of non-hybrid sedans (μ1\mu_1) is less than the mean mpg of hybrid sedans (μ2\mu_2).

Ha:μ1<μ2H_a: \mu_1 < \mu_2

(c) Random Variable:

The random variable represents the difference in miles-per-gallon between non-hybrid sedans and hybrid sedans.

(d) Distribution to Use for the Test:

Given that the sample sizes are large (n1=246n_1 = 246 and n2=256n_2 = 256), the sampling distribution of the difference in sample means (Xˉ1Xˉ2\bar{X}_1 - \bar{X}_2) can be approximated by a normal distribution.

Xˉ1Xˉ2N(μ1μ2,σ12n1+σ22n2)\bar{X}_1 - \bar{X}_2 \sim N\left(\mu_1 - \mu_2, \sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}\right)

(e) Test Statistic:

The test statistic for comparing two means is given by:

z=Xˉ1Xˉ20σ12n1+σ22n2z = \frac{\bar{X}_1 - \bar{X}_2 - 0}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}}

Where:

  • Xˉ1=27\bar{X}_1 = 27 (mean of non-hybrid mpg)
  • Xˉ2=28\bar{X}_2 = 28 (mean of hybrid mpg)
  • σ1=6.5\sigma_1 = 6.5 (standard deviation of non-hybrid mpg)
  • σ2=4.25\sigma_2 = 4.25 (standard deviation of hybrid mpg)
  • n1=246n_1 = 246 (sample size of non-hybrids)
  • n2=256n_2 = 256 (sample size of hybrids)

Now, let's calculate the test statistic:

z=27286.52246+4.252256z = \frac{27 - 28}{\sqrt{\frac{6.5^2}{246} + \frac{4.25^2}{256}}}

I'll calculate this value.The test statistic zz is approximately 2.032-2.032.

Would you like to proceed with the next steps, such as finding the p-value or making a decision based on the test statistic?

Here are 5 related questions to consider:

  1. How do you interpret the p-value in the context of this hypothesis test?
  2. What is the critical value for a one-tailed test at the 7% significance level?
  3. How does the large sample size affect the approximation to the normal distribution?
  4. What assumptions must be met for the test statistic to be valid?
  5. How would the conclusion change if the significance level was set at 5% instead of 7%?

Tip: Always remember to check the assumptions of normality and equal variances before conducting a hypothesis test for means.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Normal Distribution
Sampling Distributions

Formulas

z-test formula

Theorems

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Suitable Grade Level

Advanced High School