Math Problem Statement
You conduct a test of whether mean home prices in a certain area are $250K or not. A sample of 12 recent home sales gives an average price of $279K with a standard deviation of $32K. You find that 𝑡=𝑋¯−𝜇0S.E.(𝑋¯)=3.139342t=X¯−μ0S.E.(X¯)=3.139342 You can determine the p-value for you test using which Excel commands below? Select all that work. You might draw pictures and use symmetry to determine the correct selections.
Multiple correct question
=2*T.DIST.RT(3.139342,11)
=2*(1-T.DIST(3.139342,11, TRUE))
=2*T.DIST(-3.139342,11, TRUE)
=2*T.DIST(3.139342,11, TRUE)
Solution
To solve this problem, let's break down the details first:
We are conducting a two-tailed hypothesis test to check whether the mean home price is different from $250K or not. The test statistic was calculated as 3.139342 with 11 degrees of freedom (since the sample size is 12, degrees of freedom = 12 - 1 = 11).
Important Considerations:
- This is a two-tailed test, so we will need to calculate the p-value for both tails of the t-distribution.
- The Excel commands should correctly calculate the two-tailed p-value, which is for a right-tailed value, or equivalently for a left-tailed value.
Let's review the given options:
-
=2*T.DIST.RT(3.139342,11)
T.DIST.RT(t, df)
calculates the right-tail probability for the t-distribution.- Multiplying by 2 gives the two-tailed p-value, so this is correct for a two-tailed test.
(Correct)
-
=2*(1-T.DIST(3.139342,11, TRUE))
T.DIST(t, df, TRUE)
calculates the cumulative distribution function (CDF), or the area to the left of the given t-value.- gives the right-tail probability.
- Multiplying by 2 makes it a two-tailed test. Hence, this formula is also correct.
(Correct)
-
=2*T.DIST(-3.139342,11, TRUE)
T.DIST(-t, df, TRUE)
calculates the area to the left of a negative t-value.- In a symmetric t-distribution, the area to the left of is the same as the area to the right of .
- So multiplying this by 2 gives the two-tailed p-value.
(Correct)
-
=2*T.DIST(3.139342,11, TRUE)
T.DIST(t, df, TRUE)
gives the area to the left of the t-value.- Multiplying this by 2 would give an incorrect p-value because it includes both the left-tail and the right-tail probability for positive t.
- This is incorrect for a two-tailed test.
(Incorrect)
Correct Selections:
=2*T.DIST.RT(3.139342,11)
=2*(1-T.DIST(3.139342,11, TRUE))
=2*T.DIST(-3.139342,11, TRUE)
Would you like more details or have any questions about this explanation?
Here are 5 related questions:
- How do you interpret a p-value in hypothesis testing?
- What is the relationship between degrees of freedom and the shape of the t-distribution?
- What is the difference between one-tailed and two-tailed tests in hypothesis testing?
- How do you calculate the test statistic for a t-test?
- When should you use a t-test versus a z-test in hypothesis testing?
Tip: When conducting a two-tailed test, always remember to multiply the one-tailed probability by 2 to get the correct p-value.
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Math Problem Analysis
Mathematical Concepts
Hypothesis Testing
t-distribution
p-value Calculation
Two-tailed Test
Formulas
t = (X̄ − μ₀) / S.E.(X̄)
p-value = 2 × P(T > t)
Degrees of Freedom (df) = n - 1
Theorems
t-distribution Symmetry
Central Limit Theorem
Suitable Grade Level
Undergraduate
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