Math Problem Statement

the claim is that for 12 AM body temperatures, the mean is less than 98.6 F. the sample size is n = 6 and the test statisitic is t = -2.255. find the P-value for the hypothesis test described based on the result, what is the final conclusion? use a significance level of a = 0.05. State the null and alternative hypotheses.

Solution

We are conducting a hypothesis test for the mean body temperature. Here’s a step-by-step breakdown of the process:

Step 1: State the Null and Alternative Hypotheses

The claim is that the mean body temperature at 12 AM is less than 98.6°F. Therefore, the hypotheses are:

  • Null Hypothesis (H0H_0): The mean body temperature is 98.6°F or higher.
    H0:μ=98.6°FH_0: \mu = 98.6 \text{°F}
  • Alternative Hypothesis (HaH_a): The mean body temperature is less than 98.6°F.
    Ha:μ<98.6°FH_a: \mu < 98.6 \text{°F}

This is a left-tailed test since we are testing if the mean is less than 98.6°F.

Step 2: Determine the Test Statistic

The test statistic given is: t=2.255t = -2.255

The sample size is n=6n = 6. Degrees of freedom (dfdf) for the t-distribution is calculated as: df=n1=61=5df = n - 1 = 6 - 1 = 5

Step 3: Find the P-value

To find the P-value, we need to look up the t-distribution with 5 degrees of freedom and the test statistic t=2.255t = -2.255. Since this is a left-tailed test, the P-value is the area to the left of t=2.255t = -2.255 in the t-distribution.

Using a t-distribution table or calculator, we can find the P-value for t=2.255t = -2.255 and df=5df = 5.

Step 4: Conclusion

Once we have the P-value, we can compare it to the significance level α=0.05\alpha = 0.05:

  • If the P-value is less than 0.05, we reject the null hypothesis H0H_0.
  • If the P-value is greater than 0.05, we fail to reject the null hypothesis H0H_0.

Let me calculate the P-value for this test next.The P-value is approximately 0.0369.

Step 5: Conclusion

  • Since the P-value (0.0369) is less than the significance level α=0.05\alpha = 0.05, we reject the null hypothesis.

Final Conclusion:

There is enough evidence to support the claim that the mean body temperature at 12 AM is less than 98.6°F.


Would you like further details or have any questions? Here are some additional questions to deepen your understanding:

  1. What would happen if the significance level were set to α=0.01\alpha = 0.01?
  2. How do changes in sample size affect the P-value in t-tests?
  3. Why is the test considered a left-tailed test in this context?
  4. What assumptions are necessary when performing a t-test like this one?
  5. How would the conclusion change if the test statistic were positive instead of negative?

Tip: In hypothesis testing, always check if your test is one-tailed or two-tailed, as this affects how you calculate the P-value.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
t-Distribution
P-Value
Significance Level

Formulas

Test Statistic (t) = (Sample Mean - Population Mean) / (Sample Standard Deviation / sqrt(n))
Degrees of Freedom (df) = n - 1
P-Value Calculation for t-distribution

Theorems

Central Limit Theorem (CLT)
Student's t-distribution

Suitable Grade Level

College Statistics or Advanced High School Statistics