Math Problem Statement

what does the equation x2 − y2 + z2 = 8 look like

Solution

The equation

x2y2+z2=8x^2 - y^2 + z^2 = 8

represents a hyperboloid in three-dimensional space.

Step-by-Step Analysis:

  1. Rewriting the Equation: x2+z2y2=8x^2 + z^2 - y^2 = 8 This equation has the form of a hyperboloid of one sheet when written as: x28+z28y28=1.\frac{x^2}{8} + \frac{z^2}{8} - \frac{y^2}{8} = 1. This is the standard form of a hyperboloid of one sheet along the yy-axis.

  2. Shape and Properties:

    • It is a saddle-shaped surface extending infinitely in the x,y,x, y, and zz directions.
    • It has two asymptotic cone sections when viewed from afar.
    • Cross-sections:
      • At y=0y = 0: The equation simplifies to x2+z2=8x^2 + z^2 = 8, which is a circle of radius 8\sqrt{8}.
      • For other values of yy, the cross-sections are ellipses.

Visualization:

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Math Problem Analysis

Mathematical Concepts

Algebra
3D Geometry
Hyperboloids

Formulas

x^2 + z^2 - y^2 = 8
x^2/a^2 + z^2/a^2 - y^2/b^2 = 1 (standard form of a hyperboloid)

Theorems

Hyperboloid of one sheet

Suitable Grade Level

Grades 11-12