Math Problem Statement

The exercise involves solving hyperbola-related problems, including reducing equations to standard form, calculating eccentricity, and finding equations based on given parameters.

Solution

The exercise provided contains problems on hyperbolas. I'll break down the tasks step by step.

Problem 1

Reduce the given equations to standard form and draw the hyperbolas:

(a) 4x29y2+24x+108y324=04x^2 - 9y^2 + 24x + 108y - 324 = 0

  1. Group xx- and yy-terms: 4x2+24x9y2+108y=3244x^2 + 24x - 9y^2 + 108y = 324
  2. Factorize and complete the square for xx and yy.

(b) 16x29y296x144y288=016x^2 - 9y^2 - 96x - 144y - 288 = 0

  1. Follow a similar process to part (a), grouping and completing squares.

(c) 25x264y2+1600=025x^2 - 64y^2 + 1600 = 0

  1. Rearrange to isolate terms and bring to standard form.

Problem 2

Equation of a hyperbola centered at (4,2)(-4, 2):

  • Transverse axis: parallel to yy-axis.
  • Eccentricity: 615\frac{\sqrt{61}}{5}.
  • Distance between directrices: 506161\frac{50\sqrt{61}}{61}.

Start with the standard form of a hyperbola with vertical transverse axis: (x+4)2b2(y2)2a2=1\frac{(x+4)^2}{b^2} - \frac{(y-2)^2}{a^2} = 1 Use the given eccentricity and directrices formula to find a2a^2 and b2b^2.


Problem 3

Equation of a hyperbola centered at the origin with:

  • Transverse axis along xx-axis.
  • Length of the latus rectum =1= 1.
  • Asymptotes y=±12xy = \pm \frac{1}{2}x.

Use:

  1. Equation of hyperbola with horizontal transverse axis: x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1
  2. Latus rectum formula: 2b2a\frac{2b^2}{a}.
  3. Slope of asymptotes: y=±baxy = \pm \frac{b}{a}x.

Would you like me to work through one or all of these problems with detailed steps?

5 Questions to Explore:

  1. How do you determine the standard form of a hyperbola?
  2. What is the role of eccentricity in identifying the shape of a hyperbola?
  3. How does completing the square help in transforming equations?
  4. What is the relationship between asymptotes and the hyperbola's axes?
  5. How are latus rectum and directrix connected to hyperbola parameters?

Tip:

Always check if the hyperbola opens horizontally or vertically based on its general equation, as it determines the placement of a2a^2 and b2b^2.

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Math Problem Analysis

Mathematical Concepts

Hyperbolas
Conic Sections
Eccentricity
Standard Forms
Asymptotes

Formulas

Standard form of hyperbola: (x-h)^2/a^2 - (y-k)^2/b^2 = 1 or (y-k)^2/a^2 - (x-h)^2/b^2 = 1
Eccentricity: e = sqrt(1 + b^2/a^2) for horizontal hyperbolas
Distance between directrices: 2a/e
Equation of asymptotes: y = ±(b/a)x

Theorems

Definition of a hyperbola
Properties of hyperbolas

Suitable Grade Level

Grades 10-12